php - 无法从 html 到 php 获取动态选择列表数据。请指教

Question

<form method="POST" name="mailform" action="sendmail.php">
<fieldset>

<?php
    require_once("mysql_connect.php");
    $sql = mysql_query( " SELECT NAME FROM TABLE WHERE ID = ( SELECT ID FROM TABLE2 WHERE COLUMN = '$USERNAME') ORDER BY NAME");
    echo "<select>";
    while($row = mysql_fetch_array($sql)){
    echo "<option value='".$row["NAME"]."'>".$row["NAME"]."</option>";
    }mysql_free_result($sql);
    echo "</select>";
?>

<input type="text" name = "name" placeholder = "name Required" ><br \><br \>
<input type="checkbox"  name="instance[]" value="yes" checked="checked" \>instance1><br>
<input type="checkbox"  name="instance[]" value="Yes" \>instance2<br><br \>
<input type="submit" name="email" value="Send Mail">
</fieldset> <br \>
</form> <br \><br \>

这是代码的一部分。我需要构建 sendemail.php，它应该具有来自动态选择列表的值和来自复选框的值。

Answer 1

    <?php
        require_once("mysql_connect.php");
        $sql = mysql_query( " SELECT NAME FROM TABLE WHERE ID = ( SELECT ID FROM TABLE2 WHERE COLUMN = '$USERNAME') ORDER BY NAME");
        echo "<select name='selection'>";
        while($row = mysql_fetch_array($sql)){
        echo "<option value='".$row["NAME"]."'>".$row["NAME"]."</option>";
        }mysql_free_result($sql);


echo "</select>";
?>

用上面的代码更改你的 php 代码.. 你将从动态选择列表中获得 $_POST['selection']。

编辑:

您将获得 $_POST['instance'] 数组。

<?php
$selected = $_POST['selection'];
$instances = array();
foreach ($_POST['instance'] as $instance)
{
    $instances[] = $instance;
}
?>

现在，您将拥有 $selected 作为动态选定值，并且 $instances 具有已选中的复选框数组。