python - 将列表的副本传递给 python 中的函数

Question

我正在尝试将列表的副本传递给 python 中的函数，以便我可以弹出并附加到新列表，而不会丢失旧列表中的信息。但我遇到了麻烦。

这是我的代码

def show_magicians(magicians):
    for magician in magicians:
        print (magician.title())
        return magicians

def make_great(magicians):
    for magician in magicians:
        new_magician = magicians.pop()
        new_magicians.append(new_magician)
        print (new_magician.title() + ", is a great magician!!")
        return magicians

new_magicians = []
magicians = ['merlin', 'blaine', 'agaybi', 'copperfield']   
show_magicians(magicians)
make_great(magicians[:])
print ('\n' , magicians)
print ('\n' , new_magicians)

第二个函数应该将元素从旧列表移动到新列表，并为每个元素打印简单的语句，而不清空旧列表。问题是我只打印了 1 个元素，并且该元素是唯一移动的元素。

我做错了什么？

Answer 1

第一个魔术师处理完毕后您将返回

按如下方式更改 make_great 函数

def make_great(magicians):
    for magician in magicians:
        new_magician = magicians.pop()
        new_magicians.append(new_magician)
        print (new_magician.title() + ", is a great magician!!")
    return magicians