android - 如何使位置自动递增并避免在 ListView 中得到重复的结果？

Question

我有一个 ListView 和一个自定义适配器，我得到两个不同的结果，但只有一个被放置了两次。我该怎么做才能同时显示它们？这是我的适配器，我认为问题出在这里:

import java.util.ArrayList;
import android.content.Context;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.TextView;
public final class SearchAdapter extends ArrayAdapter<ProblemInfo> {

Context context;
ArrayList<ProblemInfo> problem;
LayoutInflater vi;
  int resource;

  public SearchAdapter(Context context, int resource, ArrayList<ProblemInfo> data) {
      super(context, resource, data);

      vi = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
      problem = data;

      }
  @Override
  public View getView(int position, View convertView, ViewGroup parent) {

   final ViewHolder holder;
   if(convertView ==null){
    convertView = vi.inflate(R.layout.searchvehiclerow,parent,false);
    holder = new ViewHolder();

    holder.tvMilage = (TextView)convertView.findViewById(R.id.item_txtMilage);
    holder.tvProblem = (TextView)convertView.findViewById(R.id.item_txtProblem);

    convertView.setTag(holder);

   } else {
    holder = (ViewHolder)convertView.getTag();

   }
   ProblemInfo ProblemInfo = problem.get(position);
   holder.tvProblem.setText(ProblemInfo.getProbdesc());
   holder.tvMilage.setText(ProblemInfo.getMilage());

   return convertView;

 }
 static class ViewHolder {
  public TextView tvMilage;
   public TextView tvProblem;
  }
}

这是我从数据库中提取的；

 public class ProblemInfoAsynTask extends AsyncTask<String, Void, Boolean>{
 @Override
  protected Boolean doInBackground(String... urls) {
 // TODO Auto-generated method stub
 String resultprob = "";
 InputStream isrProb = null;
try{

HttpPost httppost = new HttpPost(urls[0]);  
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = httpclient.execute(httppost);
int status = response.getStatusLine().getStatusCode();
if(status == 200){
HttpEntity entity = response.getEntity();
isrProb = entity.getContent();

try{
     BufferedReader reader = new BufferedReader(new InputStreamReader(isrProb,"iso-8859-1"),8);
     StringBuilder sb = new StringBuilder();
     String line = null;
     while ((line = reader.readLine()) != null) {
             sb.append(line + "\n");
     }
     isrProb.close();

     resultprob=sb.toString();
}
catch(Exception e){
     Log.e("log_tag", "Error  converting result "+e.toString());
 }
 JSONArray jArray = new JSONArray(resultprob);

for(int i=0; i<jArray.length();i++){
ProblemInfo problem = new ProblemInfo();
JSONObject json = jArray.getJSONObject(i);

problem.setMilage(json.getInt("milage"));
problem.setProbdesc(json.getString("problem_description"));
problem.setId(json.getLong("problem_id"));
probList.add(problem);
   }
return true;
}

} catch (ClientProtocolException e){
  e.printStackTrace();
} catch (IOException e){
  e.printStackTrace();
} catch (JSONException e){
  e.printStackTrace();
}


return false;
}
@Override
protected void onPostExecute(Boolean result) {

super.onPostExecute(result);
if(result == false){


}else {
SearchAdapter probAdapter = new SearchAdapter(getApplicationContext(),android.R.layout.simple_list_item_1,probList);
searchView.setAdapter(probAdapter);
}
}

这是我的数组列表

public class ProblemInfo {

    private static int milage;
    private static String probdesc;
    private long id;
    String milage2;

    public ProblemInfo()
    {

    }

    public void setMilage(int milage) {
        ProblemInfo.milage = milage;
    }

    public String getProbdesc() {
        return probdesc;
    }

    public void setProbdesc(String probdesc) {
        ProblemInfo.probdesc = probdesc;
    }

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }
    public String getMilage()
    {
        milage2 = Integer.toString(milage);
    return milage2;
    }

}

我有 milage2 到字符串，这样我就可以将它打印到文本框中我认为这是一个问题，所以我想确保它不会是

Answer 1

我修改了你的代码，我没有自己测试，但试一试..

问题信息.java

public class ProblemInfo {

private static int milage;
private static String probdesc;
private long id;
String milage2;

public ProblemInfo(String probdesc, long id,String  milage2)
{

 this.probdesc = probdesc;
 this.id = id;
 this.milage2 = milage2;  
}   

public String getProbdesc() {
    return probdesc;
}
public long getId() {
    return id;
}    
public String getMilage()
{
    milage2 = Integer.toString(milage);
    return milage2;
}

在 ProblemInfoAsynTask 中替换

problem.setMilage(json.getInt("milage"));
problem.setProbdesc(json.getString("problem_description"));
problem.setId(json.getLong("problem_id"));
probList.add(problem);

与

probList.add(new ProblemInfo(json.getString("problem_description"), json.getLong("problem_id")),    json.getInt("milage") ); 

并替换

SearchAdapter probAdapter = new    SearchAdapter(getApplicationContext(),android.R.layout.simple_list_item_1,probList);
searchView.setAdapter(probAdapter);

与

SearchAdapter probAdapter = new SearchAdapter(getApplicationContext());
searchView.setAdapter(probAdapter);
probAdapter.addAll(probList);
probAdapter.notifyDataSetChanged();

在SearchAdapter.java

替换

  public SearchAdapter(Context context, int resource, ArrayList<ProblemInfo> data) {
  super(context, resource, data);

  vi = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
  problem = data;

  }

与

public SearchAdapter(Context context) {
  super(context, R.layout.yourlyaout);

  vi = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);

  }

并使用

ProblemInfo ProblemInfo = getItem(position);

代替

ProblemInfo ProblemInfo = problem.get(position);

更新

ArrayList<ProblemInfo> probList = new ArrayList<ProblemInfo>();

我希望这能奏效，如果您遇到任何问题，请告诉我。