Python ; IF 单词在行且单词 2 不在行

Question

很抱歉成为这里的菜鸟，因为我是这方面的新手

我一直在尝试编写一个代码，它可以在行中找到某个单词，然后从第二个单词列表中进行匹配，以查看同一行中是否存在第二个单词。仅当第一个单词不存在于一行中时才打印行；这是片段和示例

keywords =("a","b","c","d")
keywords2 = ("e","f","g")
a = ("a  is a ", "a is not e","b is b", "b is not f")
for key2 in keywords2:              
    for key in keywords:                

        for line in a:

                if key2 not in line:
                    if key in line:

                        print(key+" Found in --> ")
                        print      (line)

所需的输出是

a is a
b is b

虽然我们有

a Found in --> 
a  is a 
b Found in --> 
b is b
b Found in --> 
b is not f
a Found in --> 
a  is a 
a Found in --> 
a is not e
b Found in --> 
b is b
a Found in --> 
a  is a 
a Found in --> 
a is not e
b Found in --> 
b is b
b Found in --> 
b is not f

我尝试了几种方法来实现循环但没有用

Answer 1

如果我理解正确的话，您只需要具有 keywords 值的“行” ，但不是keywords2 。在这种情况下，只需执行以下操作:

for line in a:
    if [x for x in keywords if x in line] and not [x for x in keywords2 if x in line]:
        print line

[x for x in keywords if x in line]循环遍历 keywords 中的所有项目如果它们在 line 中，则将它们添加到列表中.

[x for x in keywords2 if x in line]循环遍历 keywords2 中的所有项目如果它们在 line 中，则将它们添加到列表中.

空列表被视为 False，您需要 keywords列表不为空且 keywords2列表为空。