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我有这三个问题
SELECT COUNT(question_id) AS correct_count, uID FROM mytable WHERE id
>= 0 AND id <= 1000 AND correct = 1 AND answer_id IS NOT NULL GROUP BY user_id
SELECT COUNT(question_id) AS incorrect_count, uID FROM mytable WHERE id >= 0 AND id <= 1000 AND correct !=1 AND answer_id IS NOT NULL GROUP BY user_id
SELECT COUNT(question_id) AS null_count, uID FROM mytable WHERE id >= 0 AND id <= 1000 AND answer_id IS NULL GROUP BY user_id
如何使用 CASE 或 IF 将其作为单个查询加入?
最佳答案
SELECT user_id,
sum(id >= 0 AND id <= 1000 AND correct = 1 AND answer_id IS NOT NULL) AS correctCnt,
sum(id >= 0 AND id <= 1000 AND correct !=1 AND answer_id IS NOT NULL) AS incorrectCnt,
sum(id >= 0 AND id <= 1000 AND answer_id IS NULL) as nullCnt
FROM mytable
GROUP BY user_id
关于带有 GROUP BY 计数的 MySQL CASE,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28208905/
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