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php - 在 PHP CodeIgniter foreach 循环中从数据库中提取和更新数据

转载 作者:行者123 更新时间:2023-11-30 22:48:52 25 4
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我有一个 View ,其中包含通过 foreach 循环从数据库中显示的数据,我想要的是获取从 View 中编辑的数据并在数据库中逐个更新它,但问题是数据库如果有 where 子句,将被更新,但在我的情况下,我不知道如何从 View 获取 key (tid)到 Controller 这里是显示数据的 Controller 函数

public function bulk()
{

$pid = '';
if($this->input->post('pid'))
$pid = $this->input->post('pid');


$template['menu'] = $this->shared_model->get_flightmenus();

if($pid == '')
{
if($this->uri->segment(3))
$pid = $this->uri->segment(3);
else
$pid = $template['menu'][0]['tid'];
}

$template['pid'] = $pid;

// echo $pid;
// exit();

$template['airline'] = $this->shared_model->get_records('eat_airline');
$template['terminal'] = $this->shared_model->get_records('eat_terminal');

$template['data'] = $this->shared_model->get_recordbyvalue('eat_flight','menu_tid = '.$pid);

$template['main_content'] = $this->load->view('flight/flight_bulk_view', $template, true);
$this->load->view('includes/template', $template);



}

这是风景

    <h4><?php echo anchor('login/logout', 'Logout'); ?></h4>
<?php echo anchor('/home', 'Home'); ?>/Flights
<h2>Flights</h2>
<div>
<?php echo form_open('/flight/') ?>
<?php foreach($menu as $row){ $options[$row['tid']] = $row['m_name']; } ?>
<?php $js = 'name="pid" id="pid" onChange="this.form.submit();"'; ?>
<?php echo form_dropdown('pid', $options, $pid, $js); ?>
<?php echo form_close(); ?>
</div>
<?php echo anchor('/flight/display/1/0/'.$pid, 'Create'); ?>
<?php echo anchor('flight/bulk', 'Bulk Update'); ?>
<table>
<tr>
<td>
Name
</td>
<td>
Airline
</td>
<td>
From
</td>
<td>
Stopover
</td>
<td>
Destination
</td>
<td>
Price
</td>
<td>
Unit
</td>
<td>
Tax
</td>
<td>
Protection
</td>
<td>
Fare
</td>
<td>
Week Offer
</td>
<td>
Menu
</td>
<td>
Sort
</td>
<td>
Edit
</td>
<td>
Delete
</td>
</tr>
<?php foreach($data as $row){ ?>
<tr>
<td>
<?php echo $row['f_name'] ?>
</td>
<td>
<?php $options1[0] = ''; foreach($airline as $row1){ $options[$row1['tid']] = $row1['a_name']; } ?>
<?php echo $options[$row['airline_tid']]; ?>
</td>
<td>
<?php $options1[0] = ''; foreach($terminal as $row1){ $options[$row1['tid']] = $row1['t_name']; } ?>
<?php echo $options[$row['terminal_from_tid']]; ?>
</td>
<td>
<?php echo $row['t_stopover'] ?>
</td>
<td>
<?php $options1[0] = ''; foreach($terminal as $row1){ $options[$row1['tid']] = $row1['t_name']; } ?>
<?php echo $options[$row['terminal_destination_tid']]; ?>
</td>

<td>
<?php echo $row['f_price'] ?>
</td>
<td>
<?php echo $row['f_unit'] ?>
</td>
<td>
<?php if($row['f_tax']>0) echo 'Yes'; else echo 'No'; ?>
</td>
<td>
<?php echo $row['f_protection'] ?>
</td>
<td>
<?php echo $row['f_fare'] ?>
</td>
<td>
<?php if($row['f_weekoffer']>0) echo 'Yes'; else echo 'No'; ?>
</td>
<!--
<td>
<?php $options[0] = ''; foreach($menu as $row1){ $options[$row1['tid']] = $row1['m_name']; } ?>
<?php echo $options[$row['menu_tid']]; ?>
</td>
-->
<td>
<?php echo $row['sortindex'] ?>
</td>
<td>
<?php echo anchor('flight/display/2/'.$row['tid'].'/'.$pid, 'Edit'); ?>
</td>
<td>
<?php echo anchor('flight/display/3/'.$row['tid'].'/'.$pid, 'Delete'); ?>
</td>
</tr>
<?php } ?>
</table>

我无法想出如何完成它的逻辑

any help will be appreciated

最佳答案

我所看到的只是您想将数据从 View 传递到 Controller ,您可以通过将数据传递到 url 然后从 Controller 使用它以供将来使用。

关于php - 在 PHP CodeIgniter foreach 循环中从数据库中提取和更新数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28739685/

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