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python - 使用 Zappa 部署 Flask 应用程序时出错

转载 作者:行者123 更新时间:2023-11-30 22:45:19 26 4
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我对 zappa 很陌生。目前我正在尝试使用 zappa 部署我的 Flask 项目。

部署 Flask 应用程序时出现此错误

Traceback (most recent call last):
File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\cli.py", line 1847, in handle
sys.exit(cli.handle())

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\cli.py", line 345, in handle
self.dispatch_command(self.command, environment)

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\cli.py", line 379, in dispatch_command
self.update()

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\cli.py", line 605, in update
endpoint_url = self.deploy_api_gateway(api_id)

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\cli.py", line 1816, in deploy_api_gateway
cloudwatch_metrics_enabled=self.zappa_settings[self.api_stage].get('cloudwatch_metrics_enabled', False),

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\zappa\zappa.py", line 1014, in deploy_api_gateway
variables=variables or {}

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\botocore\client.py", line 251, in _api_call
return self._make_api_call(operation_name, kwargs)

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\botocore\client.py", line 513, in _make_api_call
api_params, operation_model, context=request_context)

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\botocore\client.py", line 566, in _convert_to_request_dict
api_params, operation_model)

File "c:\users\tanvir\virenvfordeployment\env\lib\site-packages\botocore\validate.py", line 270, in serialize_to_request
raise ParamValidationError(report=report.generate_report())

ParamValidationError: Parameter validation failed:
Invalid type for parameter restApiId, value: None, type: <type 'NoneType'>, valid types: <type 'basestring'>

有谁知道为什么会出现此错误或我该如何解决此问题?

最佳答案

我对 zappa 不太了解,但错误消息清楚地说明了您的问题:

Invalid type for parameter restApiId, value: None, type: <type 'NoneType'>, valid types: <type 'basestring'>

在我看来,您尚未设置参数 restApiId,该参数应包含 basestring 类型的值。我不确定该参数是什么,但它似乎必须与 AWS-CLI 做一些事情.

关于python - 使用 Zappa 部署 Flask 应用程序时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41228986/

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