python - 对象没有从父类(super class)继承函数？

Question

所以我不断得到

error: " AttributeError: 'Dog' object has no attribute '_Dog__name'"

事情是print(spot.get_name())工作正常。另外，当我尝试 spot.multiple_sounds() 时，也同样失败了。我认为问题是当我尝试在对象定义的函数中从父类(super class)调用对象属性时。我不明白为什么。我是根据教程完成所有这些的，并且代码与他的相同。我认为这可能是因为他使用的是 python2.x，而我使用的是spyder python3.x，但我不知道。非常感谢任何帮助。

import random
import os
import sys

class Animal:
    __name = ""
    __height = 0
    __weight = 0
    __sound = 0

    def __init__(self,name,height,weight,sound):
        self.__name = name
        self.__height = height
        self.__weight = weight
        self.__sound = sound

    def set_name(self, name):
        self.__name = name

    def get_name(self):
        return(self.__name)

    def set_height(self, height):
        self.__height = height

    def get_height(self):
        return(self.__height)

    def set_weight(self, weight):
        self.__weight = weight

    def get_weight(self):
        return(self.__weight)

    def set_sound(self, sound):
        self.__sound = sound

    def get_sound(self):
        return(self.__sound)

    def get_type(self):
        print("animal")

    def toString(self):
        return("{} is {} cm tall and {} kilograms and says {}".format(self.__name,
                                                                        self.__height,
                                                                        self.__weight,
                                                                        self.__sound))


cat = Animal('Whiskers', 33, 10,'Meow')

print(cat.toString())

class Dog(Animal):

    __owner = ""

    def __init__(self, name, height, weight, sound, owner):
        self.__owner = owner
        super().__init__(name, height, weight, sound)

    def set_owner(self,owner):
        self.__owner = owner

    def get_owner(self):
        return self.__owner

    def get_type(self):
        print("Dog")

    def toString(self):
        return "{} is {} cm tall and {} kilograms says {} and his owner is {}".format(self.__name, self.__height, self.__weight, self.__sound, self.__owner)

    def multiple_sounds(self, how_many=None):
        if how_many is None:
            print(self.getsound())
        else:
            print(self.getsound()*how_many)

spot = Dog("Spot", 53, 27, "Ruff", "Some Guy")
print(spot.get_name())
print(spot.toString())

Answer 1

在Python中，__fieldName模拟私有(private)字段，表示字段名中的两个下划线。因此，此类字段无法从派生类访问，但您仍然可以使用 getter 获取它们。