mysql - 在不同的月份和总值上加入同一个表中的两个查询

Question

我想得到一个表，该表的总和为 MONTH(NOW()) 的 member_total_point 列和 MONTH(NOW() INTERVAL 1 MONTH) 的列。如何选择表格？

编辑

我不应该在 select 上使用 [..]

这是我的新查询:

SELECT la.member_created, la.member_api_domain, la.member_api_campaign, 
      la.total, lb.total_now
FROM (SELECT member_created, member_api_domain, member_api_campaign, SUM(member_total_point) AS 'total' 
     FROM lalights_member WHERE YEAR(member_created)=YEAR(NOW()) 
     AND MONTH(member_created)= MONTH(NOW()-INTERVAL 1 MONTH) 
     GROUP BY member_api_campaign ) AS la 
LEFT JOIN (SELECT member_created,SUM(member_total_point) 
     AS 'total_now' 
     FROM lalights_member WHERE YEAR(member_created)=YEAR(NOW()) 
     AND MONTH(member_created)= MONTH(NOW()) 
     ORDER BY member_api_campaign DESC) AS lb 
ON la.member_created = lb.member_created

但是在 SQLyog 上出现这个错误:

'[total], lb.[total_now] FROM (Select member_created, member_api_domain, member_a' at line 1

我正在使用 MySQL 5.1..

示例数据:

member_created       member_api_domain  member_api_campaign member_total_point
--------------       -----------------  ------------------- ------------------
2015-09-22 18:30:20  domain             campaign             4 (september)
2015-09-22 18:30:20  domain             campaign             7 (september)
2015-08-22 18:30:20  domain             campaign             2 (august)
2015-08-22 18:30:20  domain             campaign             7 (august)
2015-09-22 18:30:20  asdf               jujuju               4 (september)
2015-08-22 18:30:20  asdf               jujuju               9 (august)

示例输出:

member_api_campaign this_month last_1month last_2month
------------------- ---------- ----------- -----------
domain              campaign   11(september) 9 (august)
asdf                jujuju     4 (september) 9 (august)

提醒一下，现在是 10 月。

Answer 1

• 更改单引号(均值字符串)作为旁引号或仅删除字段别名的引号

  'total'     for `total`
  'total_now' for `total_now`
  

• 删除 ORDER BY member_api_campaign DESC

.

SELECT la.member_created
    ,la.member_api_domain
    ,la.member_api_campaign
    ,la.total
    ,lb.total_now
FROM (
    SELECT member_created
          ,member_api_domain
          ,member_api_campaign
          ,SUM(member_total_point) AS 'total'
    FROM lalights_member
    WHERE YEAR(member_created) = YEAR(NOW())
      AND MONTH(member_created) = MONTH(NOW() - INTERVAL 1 MONTH)
    GROUP BY member_api_campaign
    ) AS la
LEFT JOIN (
    SELECT member_created
          ,SUM(member_total_point) AS 'total_now'
    FROM lalights_member
    WHERE YEAR(member_created) = YEAR(NOW())
      AND MONTH(member_created) = MONTH(NOW())
    ) AS lb ON la.member_created = lb.member_created