php - 需要从mysql中的2个表中获取数据

Question

我有两个表 filter_categories 和 filter tags

filter_categories
id | category 

filter_tags
id | filter_category_id | filter_tag

我正在编写以下查询来连接这些表

"select filter_categories.filter_category,
filter_tags.filter_tag from filter_categories JOIN filter_tags ON 
(filter_tags.filter_category_id=filter_categories.id) where   
 filter_categories.filter_id='".$_GET["id"]."' 

我用 php print_r() 得到这个结果

Array
(
[0] => Array
    (

        [filter_category] => abcty
               [filter_tag] => sdfds

    )

[1] => Array
    (

        [filter_category] => abcty

        [filter_tag] => dgdfg

    )

[2] => Array
    (

        [filter_category] => abcty

        [filter_tag] => gdgdf

    )

[3] => Array
    (

        [filter_category] => abcty

        [filter_tag] => dgdfgf

    )

[4] => Array
    (


        [filter_category] => abcty
        [filter_tag] => dsfs

    )

)

但是我需要这样获取结果

 Array
(
[0] => Array
    (

        [filter_category] => abcty
        [filter_tag] => array(
        [filter_tag] => dgdfg
        [filter_tag] => dgdfgf
        [filter_tag] => dsfs
)
)
)

[1] => Array
    (

        [filter_category] => efg
       [filter_tag] => array(

  [filter_tag] => et
[filter_tag] => yu
 [filter_tag] => op
    )
    )
   ) 

有人能帮帮我吗..该怎么做？谢谢

Answer 1

首先像这样修改您的查询以获取类别的 id

select filter_categories.id,filter_categories.filter_category,
filter_tags.filter_tag from filter_categories JOIN filter_tags ON 
(filter_tags.filter_category_id=filter_categories.id) where   
 filter_categories.filter_id='".$_GET["id"].

然后假设您的结果进入 $arrfilterALLDetails 数组，然后只需使用 for 循环修改结果，如下所示。

 $arrfilterDetails = array();
 foreach ($arrfilterALLDetails as $key => $value) {
          $arrfilterDetails[$value['id']]['filter_category'] = $value['filter_category'];
          $arrfilterDetails[$value['id']][$value['filter_tag']] = $value['filter_tag'];
        }
print_r($arrfilterDetails);

只要稍微玩一下，你就会得到你想要的结果。