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php - 使用 json 和 cURL 访问禁止的错误 403 Web 服务

转载 作者：行者123 更新时间：2023-11-30 22:24:56 25 4
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我必须做一个网络服务。于是引用了网上的一些教程，想出了下面的代码

索引.php

<html>
<head>
    <title>Form page</title>
</head>

<body>

    <form action="http://localhost:81/my%20web%20service/webservice" method="get">
        Table name:<br>
        <input type="text" name="s" value=""><br>
        <input type="submit" value="Submit">
    </form>
</body>
</html>

网络服务.php

<?php

include('connectdb.php');

$something = $_POST['s'];

$sql = "SELECT * FROM $something";
$result = $conn->query($sql);
$myArray = array();
if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
        $myArray[] = $row;
        echo "name: " . $row["name"]. " - town: " . $row["town"]. " - telephone: " . $row["telephone"]. "<br>";
    }
    //$data = json_encode($myArray);
    //var_dump($data);

    $url = 'http://localhost:81/my%20web%20service/show%details.php';
    $ch=curl_init($url);
    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_POST, 1);

    $string = http_build_query($myArray);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $string);
    $applist = curl_exec($ch);

    curl_close($ch);

} else {
    echo "0 results";
}
//$result->close();
$conn->close();
?>

connectdb.php

<?php

$servername = "localhost";
$username = "root";
$password = "";
$dbname = "webservice_trial";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} else{
    echo "connection successful.<br>";
}

?>

现在我要做的是让数据显示在另一个页面上。即我想将 webservice.php 中的数据从 json 格式传输到另一个页面(显示 details.php)。

显示细节.php

<html>
<head>
    <title>Show details page</title>
</head>

<body>
    <?php
    print_r($_POST['data']);
    ?>
</body>
</html>

我如何将 json 字符串从 Web 服务重定向到显示 details.php

我得到的是这个

connection successful.
name: hilton - town: colombo - telephone: 774933705
name: galadari - town: colombo - telephone: 112894143
name: mt. lavinia - town: mt. lavinia - telephone: 773580324
string(257) "[{"name":"hilton","town":"colombo","telephone":"774933705","description":"excellent"},{"name":"galadari","town":"colombo","telephone":"112894143","description":"best"},{"name":"mt. lavinia","town":"mt. lavinia","telephone":"773580324","description":"good"}]"
Access forbidden!

You don't have permission to access the requested object. It is either read-  protected or not readable by the server.

If you think this is a server error, please contact the webmaster.

Error 403

最佳答案

尝试使用下面的代码，将其添加到您的虚拟主机配置中

<Directory "E:/MyProjects/projectname/">
        Options Indexes FollowSymLinks MultiViews
        AllowOverride all
        Order Deny,Allow
        Allow from all
        Require all granted
</Directory>

还有

Options FollowSymLinks

到:

Options +FollowSymLinks

我用这种方法解决了同样的问题。希望对您有所帮助。

关于php - 使用 json 和 cURL 访问禁止的错误 403 Web 服务，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/35545870/

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