gpt4 book ai didi

php - 获取特定json中的mysql结果

转载 作者:行者123 更新时间:2023-11-30 22:24:07 24 4
gpt4 key购买 nike

我的项目有问题。
我正在使用 Codeigniter 及其 REST 库、Datatables jquery 插件

我的表格

Table `order`

+----+----------+-------------+---------------------+---------+-------+
| id | table_id | waiter_name | date_time | status | total |
+----+----------+-------------+---------------------+---------+-------+
| 1 | Table 1 | Waiter 1 | 2016-03-03 12:44:27 | Pending | 1500 |
+----+----------+-------------+---------------------+---------+-------+

table `orderitems`

+----+----------+-------------+----------+
| id | order_id | food_item | item_qty |
+----+----------+-------------+----------+
| 1 | 1 | Chicken Fry | 2 |
| 2 | 1 | Beef | 1 |
+----+----------+-------------+----------+

table `foodinfo`
+----+----------------+-----------+-----------+----------+
| id | food_item | status | category | price |
+----+----------------+-----------+-----------+----------+
| 1 | Chicken Fry | Available | Meat | 600 |
| 2 | Beef | Available | Meat | 300 |
+----+----------------+-----------+-----------+----------+

我的梦想数据表

ID  TABLE NAME  WAITER NAME DATE AND TIME       FOODS         STATUS    TOTAL
1 Table 1 Waiter 1 1016-03-03 12:44:24 Chicken Fry-2 Pending 1500
Beef -2

我当前的查询

$this->db->select('orderitems.*, order.*');
$this->db->from('order');
$this->db->from('orderitems');
$data = $this->db->get()->result_array();
$this->response($data);

和json

[
{
"id": "1",
"order_id": "1",
"food_item": "Chicken Fry",
"item_qty": "2",
"table_id": "Table 1",
"waiter_name": "Waiter 1",
"date_time": "2016-03-03 12:44:27",
"status": "Pending",
"total": "1500"
},
{
"id": "1",
"order_id": "1",
"food_item": "Beef",
"item_qty": "2",
"table_id": "Table 1",
"waiter_name": "Waiter 1",
"date_time": "2016-03-03 12:44:27",
"status": "Pending",
"total": "1500"
}
]

如何使用 json 和数据表获取此数据表?
codeigniter 查询生成器或 mysql 查询。

最佳答案

返回数组到 json 对象。json_decode 或 json_encode抱歉,您的问题可能不清楚。

关于php - 获取特定json中的mysql结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35812112/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com