python - Django:TypeError at/1/context 必须是字典而不是 QuerySet

Question

这是我在此网站上的第一篇文章。我现在正在学习 Django 和 Python，并尝试创建一个 Quiztool。我在创建 View 时遇到了巨大的问题，并且我很难理解如何优化查询集中的数据。在我的详细 View 中，我提出了此错误:

TypeError at /1/

context must be a dict rather than QuerySet.

Request Method: GET Request URL: http://192.168.188.146:8080/1/ Django Version: 2.0.1 Exception Type: TypeError Exception Value:

context must be a dict rather than QuerySet.

Exception Location: /home/flo/Django2.0/lib/python3.5/site-packages/django/template/context.py in make_context, line 274 Python Executable: /home/flo/Django2.0/bin/python Python Version: 3.5.3 Python Path:

['/home/flo/Django2.0/quiztool', '/home/flo/Django2.0/lib/python35.zip', '/home/flo/Django2.0/lib/python3.5', '/home/flo/Django2.0/lib/python3.5/plat-x86_64-linux-gnu', '/home/flo/Django2.0/lib/python3.5/lib-dynload', '/usr/lib/python3.5', '/usr/lib/python3.5/plat-x86_64-linux-gnu', '/home/flo/Django2.0/lib/python3.5/site-packages']

Server time: Thu, 1 Mar 2018 11:00:35 +0000

我知道我必须将查询集放入字典中，但我不知道该怎么做。

这是我的观点.py:

def index(request):
    latest_survey_list = Survey.objects.order_by('survey_id')[:5]

    context = {
        'latest_survey_list': latest_survey_list
    }
    return render(request, 'fragen/index.html', context)

def detail(request, survey_id):

    question = Survey.objects.get(pk=survey_id).question.all().values()
    question_dict = {
        'question': question
    }

    return render(request, 'fragen/detail.html', question)

这里是detail.html:

{% if question %}
    <ul>
    {% for x in question %}
    <li>{{ x.question_text }}</li>
    {% endfor %}
    </ul>
{% else %}
    <p>No questions are available.</p>
{% endif %} 

如果您需要更多信息来帮助我，请询问。

提前非常感谢，我的问候弗洛岑

Answer 1

您返回的是 question，而不是此处的 dic question_dict:

return render(request, 'fragen/detail.html', question)

应该是

return render(request, 'fragen/detail.html', question_dict)