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mysql - 我得到这样的东西 ,"Failed to load resource: the server responded with a status of 404 (Not Found)"

转载 作者:行者123 更新时间:2023-11-30 22:18:18 24 4
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我正在从数据库中获取产品的详细信息。这是我的示例代码 我无法显示产品图片!谁能帮帮我吗?

将商品详情插入数据库的代码:

<!DOCTYPE>
<?php
include("includes/db.php");
?>
<html>
<head>
<title> Inserting product</title>

<script src="//tinymce.cachefly.net/4.1/tinymce.min.js"></script>
<script>
tinymce.init({ selector:'textarea' });
</script>

</head>
<body bgcolor="skyblue">
<form action="insert_product.php" method="post" enctype="multipart/form-data">
<table align="center" width="700" border="2" bgcolor="orange">
<tr align="center">
<td colspan="7"><h2>Insert New Post Here.</h2></td>
</tr>
<tr>
<td align="right"><b>Product Title:</b></td>
<td><input type="text" name="product_title" size="50" required /></td>
</tr>
<tr>
<td align="right"><b>Product Category:</b></td>
<td>
<select name="product_cat" required>
<option>Select a categogory</option>
<?php
$get_cats = "select * from categories";
$run_cats = mysqli_query($con, $get_cats);

while($row_cats=mysqli_fetch_array($run_cats)){

$cat_id = $row_cats['cat_id'];
$cat_title = $row_cats['cat_title'];
echo "<option value='$cat_id'>$cat_title</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td align="right"><b>Product Brand:</b></td>
<td>
<select name="product_brand" required>
<option>Select a Brand</option>
<?php
$get_brands = "select * from brands";
$run_brands = mysqli_query($con, $get_brands);

while($row_brands=mysqli_fetch_array($run_brands)){

$brand_id = $row_brands['brand_id'];
$brand_title = $row_brands['brand_title'];
echo "<option value='$brand_id'>$brand_title</option>";
}
?>
</select>
</td>
</tr>
<tr>
<td align="right"><b>Product Image:</b></td>
<td><input type="file" name="product_image" required/></td>
</tr>
<tr>
<td align="right"><b>Product Price:</b></td>
<td><input type="text" name="product_price" size="50" required/></td>
</tr>
<tr>
<td align="right"><b>Product Description:</b></td>
<td><textarea name="product_desc" cols="20" rows="10"></textarea></td>
</tr>
<tr>
<td align="right"><b>Product Keywords</b></td>
<td><input type="text" name="product_keywords" size="50" required/></td>
</tr>
<tr align="center">
<td colspan="7"><b><input type="submit" name="insert_post" value="Insert Product Now"/></b></td>
</tr>
</table>
</form>
</body>
</html>
<?php
if(isset($_POST['insert_post'])){
//getting the text data from the fields.
$product_title = $_POST ['product_title'];
$product_cat = $_POST ['product_cat'];
$product_brand = $_POST ['product_brand'];
$product_price = $_POST ['product_price'];
$product_desc = $_POST ['product_desc'];
$product_keywords = $_POST ['product_keywords'];
//getting the image data from the fields.
$product_image = $_FILES['product_image'][name];
$product_image_tmp = $_FILES['product_image']['tmp_name'];

move_uploaded_file($product_image_tmp,"product_images/$product_image");

$insert_product = "insert into products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) values ('$product_cat','$product_brand','$product_title','$product_price','$product_desc',' $product_image','$product_keywords')";
$insert_pro = mysqli_query($con,$insert_product);
if($insert_pro) {
echo "<script>alert('Product has been inserted!')</script>";
echo "<script>window.open('insert_product.php','_self')</script>";
}
}
?>

函数部分。

    <?php
$con = mysqli_connect("localhost","root","","ecommerce");
//getting the categories
function getcats(){
global $con;
$get_cats = "select * from categories";
$run_cats = mysqli_query($con, $get_cats);

while($row_cats=mysqli_fetch_array($run_cats)){

$cat_id = $row_cats['cat_id'];
$cat_title = $row_cats['cat_title'];
echo "<li><a href='#'>$cat_title</a></li>";
}

}

//getting the Brands
function getBrands(){
global $con;
$get_brands = "select * from brands";
$run_brands = mysqli_query($con, $get_brands);

while($row_brands=mysqli_fetch_array($run_brands)){

$brand_id = $row_brands['brand_id'];
$brand_title = $row_brands['brand_title'];
echo "<li><a href='#'>$brand_title</a></li>";
}

}

function getpro() {
global $con;

$get_pro = "select * from products order by RAND() LIMIT 1,6";
$run_pro = mysqli_query($con, $get_pro);
while($row_pro=mysqli_fetch_array($run_pro)){
$pro_id = $row_pro['product_id'];
$pro_cat = $row_pro['product_cat'];
$pro_brand = $row_pro['product_brand'];
$pro_title = $row_pro['product_title'];
$pro_price = $row_pro['product_price'];
$pro_image = $row_pro['product_image'];
echo "
<div id='single_product'>
<h3>$pro_title</h3>
<img src='\\ecommerce\admin_area\product_images\$pro_image' width='180' height='180' />
<p><b> $pro_price </b></p>
</div>
";
}
}
?>




**The web page to display all details**
<!DOCTYPE>
<?php
include("functions/functions.php");
?>
<html>
<head>
<title>Gal Baking Services LTD online Shop.</title>
<link rel="stylesheet" href="admin_area/product_images/style.css" media="all" />
</head>
<body>
<div class="main_Wrapper">

<div class="header_wrapper">
<img id="logo" src="images/ad bunner.jpg" />
<img id="bunner" src="images/ad bunner.jpg" />
</div>
<div class="menubar">
<ul id="menu">
<li><a href="#">Home</a></li>
<li><a href="#">All products</a></li>
<li><a href="#">My account</a></li>
<li><a href="#">Sign up</a></li>
<li><a href="#">Shopping cart</a></li>
<li><a href="#">Contact Us</a></li>
</ul>
<div id="form">
<form method="get" action="result.php" enctype="multipart/form-data">
<input type="text" name="user_query" placeholder="Search a product" />
<input type="submit" name="search" value="search" />
</form>
</div>
</div>
<div class="content_wrapper">
<div id="sidebar">

<div id="sidebar_title">Categories</div>
<ul id="carts">
<?php getcats();?>
</ul>
<div id="sidebar_title">Brands</div>

<ul id="carts">
<?php getBrands();?>
</ul>

</div>
</div>
<div id="content_area">
<div id="products_box">

<?php getpro(); ?>

</div>
</div>
</div>
<div id="footer">
<h2 style="text-align:center; padding-top:30px;">&copy;2016 by www.krumblefresh.com </h2>
</div>
</div>
</body>
</html>

最佳答案

感谢大家的参与和支持。在研究了如何显示来自 mysql 数据库的图像的代码之后,我开始意识到我的代码是完美的,只是我在 insert_product.php 文件的以下几行中犯了一些愚蠢的错误,"$product_image = $_FILES['product_image'][name];"。我没有将'name'括在单引号''内。应该是,$product_image = $_FILES['product_image']['name'];.另外,在下一行*

$insert_product = "insert into products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) values ('$product_cat','$product_brand', '$product_title','$product_price','$product_desc', ' $product_image','$product_keywords')";

*, i had included a blank space inside the single quotes near $product_image.Its supposed to be ,

$insert_product = "insert into products (product_cat,product_brand,product_title,product_price,product_desc,product_image,product_keywords) values ('$product_cat','$product_brand','$product_title','$product_price','$product_desc','$product_image','$product_keywords')"; Thank you all.

关于mysql - 我得到这样的东西 ,"Failed to load resource: the server responded with a status of 404 (Not Found)",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37498515/

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