mysql - sql查询组按departname在其他表中的详细信息

Question

表:员工

EmpID: INTEGER NOT NULL
DeptID: INTEGER NOT NULL
Name: Char(40) NOT NULL
Age: INTEGER NOT NULL
Salary: INTEGER NOT NULL

表:部门

DeptID: INTEGER NOT NULL
Name: CHAR(20) NOT NULL

我们需要编写一个 SQL 查询，输出所有部门的名称，使得该部门的平均工资大于 10,00,000。输出应仅包含一列:DeptName。

试过这个:

SELECT AVG(Salary) AS avg_salary ,DeptID FROM ( SELECT DeptID, Salary FROM employee GROUP BY 1) DeptID GROUP BY DeptID HAVING avg_salary > 10;

结果:无法加入。

Answer 1

这是查询:

SELECT 
Department.name AS DeptName
FROM Department 
INNER JOIN Employee ON Department.DeptID = Employee.DeptID
GROUP BY Department.DeptID
HAVING AVG(Employee.Salary) > 1000000;