python - 从匹配值列表中删除字典

Question

我有一个字典列表，

list dict =  [
         {'children': [], 'folder': 'test2', 'parent': 'None'},
         {'children': [{'children': [], 'folder': 'arun2', 'parent': 'arun2'}],
          'folder': 'arun2',
          'parent': 'None'},
         {'children': [], 'folder': 'important', 'parent': 'None'},
         {'children': [], 'folder': 'arun', 'parent': 'None'},
         {'children': [], 'folder': 'hoi', 'parent': 'None'},
         {'children': [], 'folder': 'drafts', 'parent': 'None'},
         {'children': [], 'folder': 'Trash', 'parent': 'None'},
         {'children': [], 'folder': 'sent', 'parent': 'None'},
         {'children': [], 'folder': 'spam', 'parent': 'None'},
         {'children': [], 'folder': 'reference', 'parent': 'None'},
         {'children': [], 'folder': 'test3', 'parent': 'None'},
         {'children': [], 'folder': 'test1', 'parent': 'None'},
         {'children': [], 'folder': 'INBOX', 'parent': 'None'} 
        ]

现在我想从 list_dict 中删除包含 remove_key_list 中所有值的字典

remove_key_list = ['INBOX','sent','Trash']

例如，我想从 list dict 中删除 {'children': [], 'folder': 'INBOX', 'parent': 'None'} 并返回列表字典

我是 python 新手，如何在此处使用 del 、 lamda 函数。

Answer 1

如果您只想删除与文件夹相同的字典到您的remove_key_list之一，这应该可以完成这项工作。

list_dict =  [
         {'children': [], 'folder': 'test2', 'parent': 'None'},
         {'children': [{'children': [], 'folder': 'arun2', 'parent': 'arun2'}],
          'folder': 'arun2',
          'parent': 'None'},
         {'children': [], 'folder': 'important', 'parent': 'None'},
         {'children': [], 'folder': 'arun', 'parent': 'None'},
         {'children': [], 'folder': 'hoi', 'parent': 'None'},
         {'children': [], 'folder': 'drafts', 'parent': 'None'},
         {'children': [], 'folder': 'Trash', 'parent': 'None'},
         {'children': [], 'folder': 'sent', 'parent': 'None'},
         {'children': [], 'folder': 'spam', 'parent': 'None'},
         {'children': [], 'folder': 'reference', 'parent': 'None'},
         {'children': [], 'folder': 'test3', 'parent': 'None'},
         {'children': [], 'folder': 'test1', 'parent': 'None'},
         {'children': [], 'folder': 'INBOX', 'parent': 'None'} 
        ]

filter_list = ['INBOX', 'sent', 'Trash']

filtered_list = [d for d in list_dict if d['folder'] not in filter_list]