python 如何从该文件形成字典

Question

需要一点帮助。我有一个大文件，主要包含下面屏幕截图中的行。以字符串“zone”开头的每个 block 之间有空行。

如何形成字典，以便 test_1、test_2 和 test_3 是我的键，我的值是所有行直到空行？

第一个键的示例

键= test_1

值 = ['* fcid 0x170024 [pwwn 10:00:00:00:c9:5f:84:93] [xxxx]','* fcid 0x170016 [pwwn 50:06:0e:80:16:60 :ef:43] [xxxxxxxxx]']

有什么好的建议吗？提前致谢

正文如下:

zone name test_1 vsan xx

* fcid 0x170024 [pwwn 10:00:00:00:c9:5f:84:93] [xxx]
* fcid 0x170016 [pwwn 50:06:0e:80:16:60:ef:43] [xxxxxx]

zone name test_2 vsan xx

* fcid 0x170024 [pwwn 10:00:00:00:c9:5f:84:93] [xx]
* fcid 0x170017 [pwwn 50:06:0e:80:16:60:ef:63] [xxx]

zone name test_2 vsan yy

pwwn 10:00:00:90:fa:81:bb:f2
* fcid 0x0b00c0 [pwwn 50:06:0e:80:07:e6:2e:26]

Answer 1

您可以将正向先行断言与正则表达式结合使用。

尝试(?m)^zone\sname\s(\w+).*([\s\S]*?)(?=[\n\r]+zone\sname\s|\Z)

在行动

import re

pattern = r'(?m)^zone\sname\s(\w+).*([\s\S]*?)(?=[\n\r]+zone\sname\s|\Z)'

with open('test.txt') as f:
  data = {k: [
    i for i in v.split('\n') if i
    ] for k, v in dict(re.findall(pattern, f.read())).items()}

  print(data)

结果:

{'test_1': ['* fcid 0x170024 [pwwn 10:00:00:00:c9:5f:84:93] [xxx]', '* fcid 0x170016 [pwwn 50:06:0e:80:16:60:ef:43] [xxxxxx]'], 'test_2': ['* fcid 0x170024 [pwwn 10:00:00:00:c9:5f:84:93] [xx]', '* fcid 0x170017 [pwwn 50:06:0e:80:16:60:ef:63] [xxx]'], 'test_3': ['pwwn 10:00:00:90:fa:81:bb:f2', '* fcid 0x0b00c0 [pwwn 50:06:0e:80:07:e6:2e:26]']}

正则表达式说明:

(?m)                             # asserts multiline matching
^zone\sname\s                    # matches zone name at start of line
(                                # matching group 1
  \w+                            # Matches your key
)                                
.*                               # Matches any character but new line
(                                # Matching group 2
  [\s\S]*?                       # Matches  until...
)
(?=                              # ... this group is found
  [\n\r]+
  zone\sname                     # same as first match
  \s
  |                              # or
  \Z                             # end of string
)