mysql - select 语句中的子查询找不到派生表？

Question

我想知道是否有办法让这项工作成功。我正在推导出一个表“WHERE lie_start='green'”(以及一些我不想重复的其他条件)，需要从中获取数字(和其他一些信息)。此外，我需要带有附加条件 lie_finish='holed' 的条目数。目前我遇到错误:表 mydb.x 不存在。

SELECT 
    COUNT(*) AS total, 
    (SELECT COUNT(*) FROM x WHERE lie_finish='holed') as holed
FROM (SELECT * FROM mydb.strokes WHERE lie_start='green') as x

Answer 1

您需要重复表名。表别名无法识别:

SELECT COUNT(*) AS total, 
       (SELECT COUNT(*) FROM mydb.strokes WHERE lie_finish='holed') as holed
FROM (SELECT * FROM mydb.strokes WHERE lie_start='green') as x;

然而，这可以更简单地写成:

select count(*) as total, sum(lie_finish = 'holed') as holed
from mydb.strokes s
where lie_start = 'green';