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Python 3 使用ElementTree解析xml文件

转载 作者:行者123 更新时间:2023-11-30 22:05:52 26 4
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帮助,我正在尝试读取以下 XML 文件并从中提取数据,下面是 xml 文件的摘录,

<Variable name="Inboard_ED_mm" state="Output" type="double[]">17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154<Properties><Property name="index">25</Property><Property name="description"></Property><Property name="upperBound">0</Property><Property name="hasUpperBound">false</Property><Property name="lowerBound">0</Property><Property name="hasLowerBound">false</Property><Property name="units"></Property><Property name="enumeratedValues"></Property><Property name="enumeratedAliases"></Property><Property name="validity">true</Property><Property name="autoSize">true</Property><Property name="userSlices"></Property></Properties></Variable>

我正在尝试提取以下内容,17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154

我已经完成了这里的示例,xml.etree.ElementTree — The ElementTree XML API我可以让示例正常工作,但是当我修改上述 xml 的代码时,代码什么也没有返回!

这是我的代码,

import xml.etree.ElementTree as ET
work_dir = r"C:\Temp\APROCONE\Python"

with open(model.xml, 'rt') as f:
tree = ET.parse(f)
root = tree.getroot()

for Variable in root.findall('Variable'):
type = Variable.find('type').text
name = Variable.get('name')
print(name, type)

有什么想法吗?预先感谢您的帮助。

编辑:感谢所有发表评论的人。根据您的建议,我进行了尝试和搜索,并得到了以下代码,

with open(os.path.join(work_dir, "output.txt"), "w") as f:
for child1Tag in root.getchildren():
for child2Tag in child1Tag.getchildren():
for child3Tag in child2Tag.getchildren():
for child4Tag in child3Tag.getchildren():
for child5Tag in child4Tag.getchildren():
name = child5Tag.get('name')
if name == "Inboard_ED_mm":
print(child5Tag.attrib, file=f)
print(name, file=f)
print(child5Tag.text, file=f)

要返回以下内容,

{'name': 'Inboard_ED_mm', 'state': 'Output', 'type': 'double[]'}
Inboard_ED_mm
17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154, 17.154

我知道,这不是世界上最好的代码,任何有关如何简化代码的想法都非常受欢迎。

最佳答案

您说上面是 XML 文件的“摘录”。 XML 的结构很重要。上面的内容只是位于根节点内部吗?

for Variable in root.findall('Variable'):
print(Variable.get('name'), Variable.text)

或者它是否存在于 XML 树结构中更深的某个已知级别?

for Variable in root.findall('Path/To/Variable'):
print(Variable.get('name'), Variable.text)

或者它是否存在于 XML 树结构中某个未指定的更深层次?

for Variable in root.findall('.//Variable'):
print(Variable.get('name'), Variable.text)
<小时/>

演示最后两个:

>>> import xml.etree.ElementTree as ET
>>> src = """
<root>
<SubNode>
<Variable name='x'>17.154, ..., 17.154<Properties>...</Properties></Variable>
<Variable name='y'>14.174, ..., 15.471<Properties>...</Properties></Variable>
</SubNode>
</root>"""
>>> root = ET.fromstring(src)
>>> for Variable in root.findall('SubNode/Variable'):
print(Variable.get('name'), Variable.text)


x 17.154, ..., 17.154
y 14.174, ..., 15.471
>>>
>>> for Variable in root.findall('.//Variable'):
print(Variable.get('name'), Variable.text)


x 17.154, ..., 17.154
y 14.174, ..., 15.471
<小时/>

更新

根据您的新/更清晰/更新的问题,您正在寻找:

for child in root.findall("*/*/*/*/Variable[@name='Inboard_ED_mm']"):
print(child.attrib, file=f)
print(child.get('name'), file=f)
print(child.text, file=f)

for child in root.findall(".//Variable[@name='Inboard_ED_mm']"):
print(child.attrib, file=f)
print(child.get('name'), file=f)
print(child.text, file=f)

有了标签 1 到 4 的确切标签名,我们可以为您提供更准确的 XPath,而不是依赖于 */*/*/*/

关于Python 3 使用ElementTree解析xml文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52877083/

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