python正则表达式匹配美元值

Question

这个问题已经有答案了:

re.findall behaves weird (3 个回答)

已关闭 4 年前。

我正在尝试在 Python 中提出一个用于美元值(value)搜索的正则表达式。我在 SO 帖子上查看并尝试了很多解决方案，但没有一个非常有效。

我想出的正则表达式是:

[Ss]        # OCR will mess up with dollar signs, so I'm specifically looking for S and s as the starting of what I'm looking for
\d+         # any digits to start off
(,\d{3})*   # include comma for thousand splits, can have multiple commas
(.\d{2})?   # include dot and 2 decimals, but only one occurrence of this part

我在以下示例中尝试过此操作:

t = "sixteen thousand three hundred and thirty dollars (s16,330.00)"
r = "[Ss]\d+(,\d{3})*(.\d{2})?"

re.findall(pattern=r, string=t)

我得到了:

[(',330', '.00')]

正则表达式文档说:

If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group. Empty matches are included in the result.

但它甚至没有得到整数部分。

我的问题是:我真的很想找到s16,330.00作为一个整体。有解决办法吗？

Answer 1

删除捕获组以允许 findall 返回完全匹配的字符串:

>>> t = "sixteen thousand three hundred and thirty dollars (s16,330.00)"
>>> r = r"[Ss]\d+(?:,\d{3})*(?:\.\d{2})?"
>>> re.findall(pattern=r, string=t)
['s16,330.00']

另请注意，正则表达式中的点需要转义