php - 将数据从 ajax 传递到 laravel 5.1 Controller 以保存到 mysql？

Question

我需要将数据从 jquery(版本 1.9.1)传递到我的 Controller (Laravel 5.1)，然后将其保存到 mysql。

如何做到这一点并传递变量槽？到目前为止它没有用。如需更多详细信息，请询问我。

j查询:

 $(".tic").click(function(){
    var slot = $(this).attr('id');
    playerTurn(turn, slot);
    $.ajax({
        url: '/addhistory',
        type: 'POST',
        data: { _token: {{ csrf_token() }}, moves: slot },
        success: function()
        {
            alert("Data has been saved successfully!");
        }
    });
 });

Controller :

 public function addhistory(Request $request)
    {
        $history = new History();
        $history->game_id = Game::orderBy('id', 'desc')->first()->id;
        $history->moves = $request->moves;
        $history->save();
        return redirect()->back();
    }

路线:

Route::post('/addhistory', 'GameController@addhistory');

控制台错误:

(index):198 Uncaught ReferenceError: HAmcYRScL9puItnUGbd2kHx.... is not defined
    at HTMLAnchorElement.<anonymous> ((index):198)
    at HTMLAnchorElement.dispatch (191.js:3)
    at HTMLAnchorElement.v.handle (191.js:3)

---

191.js文件是1.9.1的jquery版本

Answer 1

你可以使用这段代码，它可能有效

 $(".tick").click(function (event) {
    event.preventDefault();
    $('.loading').show();
    var form = $(this);
    var data = new FormData($(this)[0]);
    var url = form.attr("action");
    $.ajax({
        type: "POST",
        url: url,
        data: data,
        async: false,
        cache: false,
        contentType: false,
        processData: false,
        success: function (data) {
           alert("Data has been saved successfully.");
        },
        error: function (xhr, textStatus, errorThrown) {
            alert(errorThrown);
        }
    });
    return false;
});