python - 将元素保留在另一个列表中包含的元组列表中

Question

所以我有这个坏词列表:

badWords = ["nu", "să", "o", "și", "de", "i", "pe", "cu", "ce", "mai", "la", "în", "un", "se", "mi", "eu", "ca",
                "că"]

我有这个格式的双重列表:

word_list = [(673, 'de'), (606, 'și'), (518, 'o'), (486, 'să'), (484, 'nu'), (469, 'i'), (348, 'pe'), (309, 'răzvan'), (308, 'cu'), (304, 'ce'), (302, 'mai')]

我尝试这样做，以便删除与我的坏词列表匹配的条目

for x in range(len(word_list)):
    for y in range(len(word_list[x])):
        for word in badWords:
            if(word_list[x][y] == word):
                word_list.remove(x)

但我明白了:

Error: list.remove(x): x not in list

Answer 1

您最好使用 list comprehension 创建一个新列表，并仅保留那些在 badWords 中不存在第二项的元组:

[i for i in word_list if i[1] not in badWords]
# [(309, 'răzvan')]