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python - vpython中的椭圆轨道

转载 作者:行者123 更新时间:2023-11-30 21:56:15 24 4
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我有以下代码。该代码是围绕其他物体绕轨道运行的物体的模拟,例如太阳系。当你运行它时,物体会沿着圆形轨道运行。

import math
from vpython import *
lamp = local_light(pos=vector(0,0,0), color=color.yellow)
# Data in units according to the International System of Units
G = 6.67 * math.pow(10,-11)

# Mass of the Earth
ME = 5.973 * math.pow(10,24)
# Mass of the Moon
MM = 7.347 * math.pow(10,22)
# Mass of the Mars
MMa = 6.39 * math.pow(10,23)
# Mass of the Sun
MS = 1.989 * math.pow(10,30)
# Radius Earth-Moon
REM = 384400000
# Radius Sun-Earth
RSE = 149600000000
RMS = 227900000000
# Force Earth-Moon
FEM = G*(ME*MM)/math.pow(REM,2)
# Force Earth-Sun
FES = G*(MS*ME)/math.pow(RSE,2)
# Force Mars-Sun
FEMa = G*(MMa*MS)/math.pow(RMS,2)

# Angular velocity of the Moon with respect to the Earth (rad/s)
wM = math.sqrt(FEM/(MM * REM))
# Velocity v of the Moon (m/s)
vM = wM * REM
print("Angular velocity of the Moon with respect to the Earth: ",wM," rad/s")
print("Velocity v of the Moon: ",vM/1000," km/s")

# Angular velocity of the Earth with respect to the Sun(rad/s)
wE = math.sqrt(FES/(ME * RSE))
# Angular velocity of the Mars with respect to the Sun(rad/s)
wMa = math.sqrt(FEMa/(MMa * RMS))

# Velocity v of the Earth (m/s)
vE = wE * RSE
# Velocity v of the Earth (m/s)
vMa = wMa * RMS
print("Angular velocity of the Earth with respect to the Sun: ",wE," rad/s")
print("Velocity v of the Earth: ",vE/1000," km/s")


# Initial angular position
theta0 = 0

# Position at each time
def positionMoon(t):
theta = theta0 + wM * t
return theta

def positionMars(t):
theta = theta0 + wMa * t
return theta

def positionEarth(t):
theta = theta0 + wE * t
return theta


def fromDaysToS(d):
s = d*24*60*60
return s

def fromStoDays(s):
d = s/60/60/24
return d

def fromDaysToh(d):
h = d * 24
return h

# Graphical parameters
print("\nSimulation Earth-Moon-Sun motion\n")
days = 365
seconds = fromDaysToS(days)
print("Days: ",days)
print("Seconds: ",seconds)

v = vector(384,0,0)
E = sphere(pos = vector(1500,0,0), color = color.blue, radius = 60, make_trail=True)
Ma = sphere(pos = vector(2300,0,0), color = color.orange, radius = 30, make_trail=True)
M = sphere(pos = E.pos + v, color = color.white,radius = 10, make_trail=True)
S = sphere(pos = vector(0,0,0), color = color.yellow, radius=700)

t = 0
thetaTerra1 = 0
dt = 5000
dthetaE = positionEarth(t+dt)- positionEarth(t)
dthetaM = positionMoon(t+dt) - positionMoon(t)
dthetaMa = positionMars(t+dt) - positionMars(t)
print("delta t:",dt,"seconds. Days:",fromStoDays(dt),"hours:",fromDaysToh(fromStoDays(dt)),sep=" ")
print("Variation angular position of the Earth:",dthetaE,"rad/s that's to say",degrees(dthetaE),"degrees",sep=" ")
print("Variation angular position of the Moon:",dthetaM,"rad/s that's to say",degrees(dthetaM),"degrees",sep=" ")

while t < seconds:
rate(500)
thetaEarth = positionEarth(t+dt)- positionEarth(t)
thetaMoon = positionMoon(t+dt) - positionMoon(t)
thetaMars = positionMars(t+dt) - positionMars(t)
# Rotation only around z axis (0,0,1)
E.pos = rotate(E.pos,angle=thetaEarth,axis=vector(0,1,0))
Ma.pos = rotate(Ma.pos,angle=thetaMars,axis=vector(0,1,0))
v = rotate(v,angle=thetaMoon,axis=vector(0,1,0))
M.pos = E.pos + v
t += dt

我想知道如何将轨道路径更改为椭圆形?我尝试了多种方法,但未能找到任何解决方案。

谢谢。谢谢

最佳答案

这看起来更像是一个物理问题,而不是一个编程问题。问题是,在计算速度和线性积分位置(例如 v * dt)时,您假设每个轨道都是圆形的。这不是计算轨道物体轨迹的方法。

为了简单起见,我们假设所有质量都是点质量,因此不需要考虑任何奇怪的重力梯度或姿态动力学。

从那里,您可以引用这个麻省理工学院页面。 ( http://web.mit.edu/12.004/TheLastHandout/PastHandouts/Chap03.Orbital.Dynamics.pdf ) 轨道动力学。在第七页上,有一个方程将距中心体的径向位置与多个轨道参数的函数联系起来。看起来除了轨道的偏心率之外,你拥有所有参数。如果您有详细的短暂数据或远点/近点信息,您可以在线查找或计算它。

从该方程中,您将在分母中看到 phi - phi_0 项。这就是俗称的卫星真正的异常现象。您可以从 0 到 360 迭代这个真实异常参数来查找径向距离,而不是时间,并且从真实异常、倾角、到升交点的直角以及近点参数,您可以在以下位置找到 3D 笛卡尔坐标:特定的真实异常。

从真正的异常出发并不是那么简单。您需要找到偏心异常,然后找到每个偏心异常步骤的平均异常。现在,您已经得到了作为时间函数的平均异常值。您可以在使用 v * dt 计算位置的“节点”之间进行线性插值。您可以使用 vis-viva 方程计算速度,dt 是计算的时间步长之间的差值。

在每个时间步,您都可以在 python 程序中更新卫星的位置,它将正确绘制您的轨迹。

有关真正异常的更多信息,维基百科对此有很好的描述:https://en.wikipedia.org/wiki/True_anomaly

有关轨道元素的更多信息(需要从径向位置转换为笛卡尔坐标):https://en.wikipedia.org/wiki/Orbital_elements

关于python - vpython中的椭圆轨道,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55537402/

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