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c# - 使用 Lockbits 替换图像的颜色

转载 作者:行者123 更新时间:2023-11-30 21:53:57 38 4
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首先,我会指出我将接受 C# 或 VB.NET 解决方案。

我正在尝试重构这段旧代码,以避免使用 GetPixel/SetPixel 方法的坏习惯和性能低下:

<Extension>
Public Function ChangeColor(ByVal sender As Image,
ByVal oldColor As Color,
ByVal newColor As Color) As Image

Dim bmp As New Bitmap(sender.Width, sender.Height, sender.PixelFormat)

Dim x As Integer = 0
Dim y As Integer = 0

While (x < bmp.Width)

y = 0
While y < bmp.Height
If DirectCast(sender, Bitmap).GetPixel(x, y) = oldColor Then
bmp.SetPixel(x, y, newColor)
End If
Math.Max(Threading.Interlocked.Increment(y), y - 1)
End While
Math.Max(Threading.Interlocked.Increment(x), x - 1)

End While

Return bmp

End Function

所以,在阅读了投票最多的解决方案后 here 使用 LockBits 方法,我试图使代码适应我的需要,使用 Color 作为参数而不是字节序列(因为本质上它们是相同的):

<Extension>
Public Function ChangeColor(ByVal sender As Image,
ByVal oldColor As Color,
ByVal newColor As Color) As Image

Dim bmp As Bitmap = DirectCast(sender.Clone, Bitmap)

' Lock the bitmap's bits.
Dim rect As New Rectangle(0, 0, bmp.Width, bmp.Height)
Dim bmpData As BitmapData = bmp.LockBits(rect, ImageLockMode.ReadWrite, bmp.PixelFormat)

' Get the address of the first line.
Dim ptr As IntPtr = bmpData.Scan0

' Declare an array to hold the bytes of the bitmap.
Dim numBytes As Integer = (bmpData.Stride * bmp.Height)
Dim rgbValues As Byte() = New Byte(numBytes - 1) {}

' Copy the RGB values into the array.
Marshal.Copy(ptr, rgbValues, 0, numBytes)

' Manipulate the bitmap.
For i As Integer = 0 To rgbValues.Length - 1 Step 3

If (Color.FromArgb(rgbValues(i), rgbValues(i + 1), rgbValues(i + 2)) = oldColor) Then
rgbValues(i) = newColor.R
rgbValues(i + 1) = newColor.G
rgbValues(i + 2) = newColor.B
End If

Next i

' Copy the RGB values back to the bitmap.
Marshal.Copy(rgbValues, 0, ptr, numBytes)

' Unlock the bits.
bmp.UnlockBits(bmpData)

Return bmp

End Function

我对扩展方法有两个问题:第一个是,如果像素格式不是原始示例中的 Format24bppRgb ,那么一切都会出错:循环中抛出“IndexOutOfRange”异常。我想这是因为我正在读取 3 个字节 (RGB) 而不是 4 个字节 (ARGB),但我不确定如何使其适应我可以传递给函数的任何源像素格式。

第二个是,如果我按照原始 C# 示例使用 Format24bppRgb,颜色将变为黑色。

请注意,我不确定我链接到的 C# 问题中给出的原始解决方案是否错误,因为根据他们的评论,它似乎在某种程度上是错误的。

这就是我尝试使用它的方式:

    ' This function creates a bitmap of a solid color.
Dim srcImg As Bitmap = ImageUtil.CreateSolidcolorBitmap(New Size(256, 256), Color.Red)
Dim modImg As Image = srcImg.ChangeColor(Color.Red, Color.Blue)

PictureBox1.BackgroundImage = srcImg
PictureBox2.BackgroundImage = modImg

最佳答案

I suppose this is because I'm reading 3 bytes (RGB) instead of 4 (ARGB)

是的,这就是重点。如果要操作原始图像内容,则必须依赖PixelFormat。并且您必须区分索引格式(8bpp 或更少),其中 BitmapData 中的像素不是颜色,而是调色板的索引。

public void ChangeColor(Bitmap bitmap, Color from, Color to)
{
if (Image.GetPixelFormatSize(bitmap.PixelFormat) > 8)
{
ChangeColorHiColoredBitmap(bitmap, from, to);
return;
}

int indexFrom = Array.IndexOf(bitmap.Palette.Entries, from);
if (indexFrom < 0)
return; // nothing to change

// we could replace the color in the palette but we want to see an example for manipulating the pixels
int indexTo = Array.IndexOf(bitmap.Palette.Entries, to);
if (indexTo < 0)
return; // destination color not found - you can search for the nearest color if you want

ChangeColorIndexedBitmap(bitmap, indexFrom, indexTo);
}

private unsafe void ChangeColorHiColoredBitmap(Bitmap bitmap, Color from, Color to)
{
int rawFrom = from.ToArgb();
int rawTo = to.ToArgb();

BitmapData data = bitmap.LockBits(new Rectangle(Point.Empty, bitmap.Size), ImageLockMode.ReadWrite, bitmap.PixelFormat);
byte* line = (byte*)data.Scan0;
for (int y = 0; y < data.Height; y++)
{
for (int x = 0; x < data.Width; x++)
{
switch (data.PixelFormat)
{
case PixelFormat.Format24bppRgb:
byte* pos = line + x * 3;
int c24 = Color.FromArgb(pos[0], pos[1], pos[2]).ToArgb();
if (c24 == rawFrom)
{
pos[0] = (byte)(rawTo & 0xFF);
pos[1] = (byte)((rawTo >> 8) & 0xFF);
pos[2] = (byte)((rawTo >> 16) & 0xFF);
}
break;
case PixelFormat.Format32bppRgb:
case PixelFormat.Format32bppArgb:
int c32 = *((int*)line + x);
if (c32 == rawFrom)
*((int*)line + x) = rawTo;
break;
default:
throw new NotSupportedException(); // of course, you can do the same for other pixelformats, too
}
}

line += data.Stride;
}

bitmap.UnlockBits(data);
}

private unsafe void ChangeColorIndexedBitmap(Bitmap bitmap, int from, int to)
{
int bpp = Image.GetPixelFormatSize(bitmap.PixelFormat);
if (from < 0 || to < 0 || from >= (1 << bpp) || to >= (1 << bpp))
throw new ArgumentOutOfRangeException();

if (from == to)
return;

BitmapData data = bitmap.LockBits(
new Rectangle(Point.Empty, bitmap.Size),
ImageLockMode.ReadWrite,
bitmap.PixelFormat);

byte* line = (byte*)data.Scan0;

// scanning through the lines
for (int y = 0; y < data.Height; y++)
{
// scanning through the pixels within the line
for (int x = 0; x < data.Width; x++)
{
switch (bpp)
{
case 8:
if (line[x] == from)
line[x] = (byte)to;
break;
case 4:
// First pixel is the high nibble. From and To indices are 0..16
byte nibbles = line[x / 2];
if ((x & 1) == 0 ? nibbles >> 4 == from : (nibbles & 0x0F) == from)
{
if ((x & 1) == 0)
{
nibbles &= 0x0F;
nibbles |= (byte)(to << 4);
}
else
{
nibbles &= 0xF0;
nibbles |= (byte)to;
}

line[x / 2] = nibbles;
}
break;
case 1:
// First pixel is MSB. From and To are 0 or 1.
int pos = x / 8;
byte mask = (byte)(128 >> (x & 7));
if (to == 0)
line[pos] &= (byte)~mask;
else
line[pos] |= mask;
break;
}
}

line += data.Stride;
}

bitmap.UnlockBits(data);
}

关于c# - 使用 Lockbits 替换图像的颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33562053/

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