python - 查找奇偶校验异常值 Python

Question

def find_outlier(lstOfints):
  for integer in lstOfints:
    #print(integer)
    if integer % 2 ==1:
      integer
    elif integer % 2 == 0:
      integer
  return integer

我不断得到错误的答案，但我不知道发生了什么事。这就是问题所在:

You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a method that takes the array as an argument and returns this "outlier" N.

Answer 1

这似乎对我有用:

def find_outlier(lstOfints):
    if lstOfints[0] % 2 == 1 and lstOfints[1] % 2 == 1:
        for integer in lstOfints[2::]:
            if integer % 2 == 0:
                return integer
    elif lstOfints[0] % 2 == 0 and lstOfints[1] % 2 == 0:
        for integer in lstOfints[2::]:
            if integer % 2 == 1:
                return integer
    else:
        if lstOfints[0] % 2 == lstOfints[2] % 2:
            return lstOfints[1]
        else:
            return lstOfints[0]

首先，我看看这个列表是全是赔率还是全是偶数(除了异常值)。然后，如果它是偶数，它会遍历列表寻找奇数，如果列表都是奇数，则相同。但是，如果离群值位于前两个数字中，则它会通过将模数与列表中第三个数字的模数进行比较来检查离群值是第一个数字还是第二个数字。