c - 如何使用 while 循环返回启动程序？

Question

当我选择它时，我遇到了一个问题，它总是退出我的程序，当我输入错误的选择时，我必须退出吗？

我的循环出了什么问题？请帮助我，因为循环我遇到了严重的问题。这是一个基本概念，但我的大脑已经陈旧且卡住了。

你能帮我理解循环以返回到程序的开头吗？

谢谢

#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
main()
{
    char choice,name[40],date[40],note[500],;
    int password;
    int ch;
    printf("\n\n\t\tMAIN MENU:");
    printf("\n\n\tADD RECORD\t[1]");
    printf("\n\tVIEW RECORD\t[2]");
    printf("\n\tEDIT RECORD\t[3]");
    printf("\n\tDELETE RECORD\t[4]");
    printf("\n\tEDIT PASSWORD\t[5]");
    printf("\n\tEXIT\t\t[6]");
    printf("\n\n\tENTER YOUR CHOICE:");
    scanf("%d",&ch);

    switch(ch)
        do{
            {
                opcase 1:
                    printf("\n\tEDIT RECORD\t[3]");
                    printf("\n\tEDIT RECORD\t[3]");
                    printf("\n\tEDIT RECORD\t[3]");
                    printf("\n\tEDIT RECORD\t[3]");
                    break;

                case 2:
                    printf("\n\tEDIT RECORD\t[3]");                      
                    break;

                case 3:
                    printf("\n\tEDIT RECORD\t[3]");
                    break;

                case 4:
                    printf("\n\tEDIT RECORD\t[3]");
                    break;

                case 5: 
                    printf("\n\tEDIT RECORD\t[3]");
                    break;

                case 6:
                    printf("\n\n\t\tTHANK YOU FOR USING THE SOFTWARE BY:\n\n\tBIJAY PURI\n\n\tBHANU POUDEL\n\n\tNRIPASH AYER...");
                    getch();
                    exit(0);

                default:
                    printf("\nYOU ENTERED WRONG CHOICE..");
                    printf("\nPRESS ANY KEY TO TRY AGAIN");
                    getch();
                    break;
                }     
            }
            while(ch!=6);          
  return 0; 
  getch();
}

Answer 1

将您的 do..while 循环放在 switch 案例之外。

提示:如果您正确缩进了代码，您可能已经自己解决了这个问题。

正确的语法:

do 
  {

    //do something
        switch (variable)
        {
        //case 
        break;
        }
  }
while (condition)

<小时/>

编辑:

下面是您的代码的工作版本[在Linux上]。请仔细注意更改。

#include <stdio.h>
#include <stdlib.h>

int main()
{
        char choice,name[40],date[40],note[500];
        int password;
        int ch;

        printf("\n\n\t\tMAIN MENU:");
        printf("\n\n\tADD RECORD\t[1]");
        printf("\n\tVIEW RECORD\t[2]");
        printf("\n\tEDIT RECORD\t[3]");
        printf("\n\tDELETE RECORD\t[4]");
        printf("\n\tEDIT PASSWORD\t[5]");
        printf("\n\tEXIT\t\t[6]");


        do{
        printf("\n\n\tENTER YOUR CHOICE:");
        scanf("%d",&ch);
                switch(ch)

                {
                        case 1:
                            printf("\n\tEDIT RECORD\t[3]\n");
                            printf("\n\tEDIT RECORD\t[3]\n");
                            printf("\n\tEDIT RECORD\t[3]\n");
                            printf("\n\tEDIT RECORD\t[3]\n");

                                break;
                        case 2:    
                                printf("\n\tEDIT RECORD\t[3]");                      
                                break;
                        case 3:
                                printf("\n\tEDIT RECORD\t[3]");
                                break;
                        case 4:
                                printf("\n\tEDIT RECORD\t[3]");
                                break;
                        case 5:            
                                printf("\n\tEDIT RECORD\t[3]");
                                break;
                        case 6:
                                printf("\n\n\t\tTHANK YOU FOR USING THE SOFTWARE BY:\n\n\tBIJAY PURI\n\n\tBHANU POUDEL\n\n\tNRIPASH AYER...");
                                exit(0);
                        default:
                                printf("\nYOU ENTERED WRONG CHOICE..");
                                printf("\nPRESS ANY KEY TO TRY AGAIN");
                                break;
                }
        } while(1);          //no need to check conditions here, redundant.

        return 0 ; 
}