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c - 在 C 语言中,赋值使指针来自整数,无需强制转换[默认启用]

转载 作者:行者123 更新时间:2023-11-30 21:47:09 25 4
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代码:

#include<stdio.h>
#include<stdlib.h>
struct node
{
int data;
struct node *next;
};
struct node *head,*temp;
int insert_end(int);
int insert_begin(int);
int display(void);
int delete_end(void);
int delete_begin(void);

int main()
{
head=(struct node *)malloc(sizeof(struct node));
temp=(struct node *)malloc(sizeof(struct node));
head->next = -1;
int choice,a,b;
label:
printf("\n\t1.insert_end 2. insert_begin 3.\n delete_end 4.delete_begin \n5.display 6.exit ");
scanf( "%d",&choice);
switch ( choice )
{
case 1:
{
printf("\tenter the no to be insert at the end ");
scanf("%d",&a);
insert_end (a);

goto label;

}
case 2:
printf("\tenter the no to be insert at the beginnig ");
scanf("%d",&a);
insert_begin (a);

goto label;

case 3:
{
b = delete_end();
if ( b == 0)
{
printf( " \t\tfailed ! ! \n");}
else
{
printf( " \t\t success ! ! \n");}

goto label;
}

case 4:
{
b = delete_begin();
if ( b == 0)
{
printf( " \t\tfailed ! ! \n");}
else
{
printf( " \t\t success ! ! \n");}

goto label;
}
case 5:
{
temp =head ;
display();
goto label;
}
case 6:
{
exit (0);
}
default:
{
printf( "wrong options");
goto label;
}

}
}

int insert_end ( int a )
{
temp = head;
while (1)
{
if (temp->next == -1)
{
temp->data =a;
temp->next =0;
return 0;
}
else if (temp->next == 0)
{
temp->next = malloc(sizeof ( struct node));
temp =temp->next;
temp->data =a;
temp->next =0;
return 0;
}
else
{
temp = temp->next;
}
}
}


int display()
{
temp=head;
while (1)
{
if (head->next == -1)
{
printf( "\tEmpty ! ! !\t\n");
break;
}
else if ((head->next == 0) )
{
printf( " %d ", head->data);
break;
}
else if (temp->next != 0 )
{
printf (" %d ->", temp->data );
temp =temp->next ;
}
else if (temp->next == 0 )
{
printf(" %d ", temp->data);
return 0;
}
}
}


int insert_begin(int a)
{
if(head->next == -1)
{
head->data =a;
head->next=0;
return 1;
}
else
{
temp =malloc(sizeof ( struct node ));
temp->data =a;
temp->next = head;
head = temp;
return 1;
}
}

int delete_end (void)
{
temp=head;
while (1)
{
if (head->next == -1)
{
return 0;
}
else if (head->next == 0)
{
head->next = -1;
return 1;
}
else if (temp->next->next == 0)
{
temp->next =0;
return 1;
}
else
temp=temp->next;
}
}


int delete_begin(void)
{
if ( head->next == -1)
{
return 0;
}
else if ( head -> next == 0)
{
head->next = -1;
return 1;
}
else
{
head=head->next;
return 1;
}
}

error:

linkedlist1.c: In function ‘main’:

linkedlist1.c:19:12: warning: assignment makes pointer from integer without a cast [enabled by default]

head->next = -1;
^
linkedlist1.c: In function ‘insert_end’:

linkedlist1.c:87:16: warning: comparison between pointer and integer [enabled by default]
if (temp->next == -1)
^
linkedlist1.c: In function ‘display’:

linkedlist1.c:115:16: warning: comparison between pointer and integer [enabled by default]
if (head->next == -1)
^
linkedlist1.c: In function ‘insert_begin’:

linkedlist1.c:141:15: warning: comparison between pointer and integer [enabled by default]
if(head->next == -1)
^
linkedlist1.c: In function ‘delete_end’:

linkedlist1.c:162:16: warning: comparison between pointer and integer [enabled by default]
if (head->next == -1)
^
linkedlist1.c:168:12: warning: assignment makes pointer from integer without a cast [enabled by default]
head->next = -1;
^
linkedlist1.c: In function ‘delete_begin’:

linkedlist1.c:184:17: warning: comparison between pointer and integer [enabled by default]
if ( head->next == -1)
^
linkedlist1.c:190:12: warning: assignment makes pointer from integer without a cast [enabled by default]
head->next = -1;
^

当我尝试使用 GCC 进行编译时,我最终收到一条警告:“赋值使指针来自整数而不进行强制转换[默认启用]请帮助我解决上述警告。我不知道错误是什么.

最佳答案

通过“警告”,您还会得到一个字符串编号,其中出现“警告”。请给出出现错误的字符串

我第一次没有看到你的警告

只需将 -1 替换为 NULL 或将 -1 替换为 (void *)-1

当然标准应该写成NULL,但如果你确实想要,你可以写(void *)-1

关于c - 在 C 语言中,赋值使指针来自整数,无需强制转换[默认启用],我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26083769/

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