c - 嗨，有人可以帮我解决这个循环吗

Question

很难说出这里问的是什么。这个问题是含糊的、模糊的、不完整的、过于宽泛的或修辞性的，无法以目前的形式得到合理的回答。如需帮助澄清此问题以便重新打开它， visit the help center 。

已关闭 10 年前。

很抱歉问这个问题，但我没有其他地方可去，而且我无法找到解决方案。我很擅长编程语言 Pascal，所以这种 C 语言对我来说似乎很熟悉，但是添加一个 if 函数来改变 while 循环的整个结构对我来说太复杂了。请提供任何帮助，我们将不胜感激。

The array variable consists of a sequence of ten numbers. Inside the while loop, you must write two if conditions, which change the flow of the loop in the following manner (without changing the printf command):

• If the current number which is about to be printed is less than 5, don't print it.
• If the current number which is about to be printed is greater than 10, don't print it and stop the loop.
  
  Notice that if you do not advance the iterator variable i and use the continue derivative, you will get stuck in an infinite loop.

#include <stdio.h>

int main()
{
    int array[] = {1, 7, 4, 5, 9, 3, 5, 11, 6, 3, 4};
    int i = 0;

    while (i < 10)
    {
        /* your code goes here */

        printf("%d\n", array[i]);
        i++;
    }
    return 0;
}

Answer 1

它正在测试您对 C 流控制的理解。您正在寻找的是这样的:

if (array[i] < 5) {i++; continue; }  // increment, go back to while
if (array[i] > 10) break;            // leave while