c - 尝试用C计算年龄

Question

你能告诉我我的代码有什么问题吗？

#include <stdlib.h>
#include <stdio.h>

int main()

{

    int CurrentYear;
    int BornYear;
    int age = CurrentYear - BornYear;

    printf("What year is it?\n");
    scanf("%d", &CurrentYear);
    //printf("Year check: %d\n", CurrentYear);
    printf("What year you were born?\n");
    scanf("%d", &BornYear);
    //printf("Year check: %d\n", BornYear);
    printf("You are %d years old\n", age);
    return 0;
}

结果我得到了一些奇怪的数字。

Answer 1

C 中的表达式不是公式。这:

int age = CurrentYear - BornYear;

并不意味着age的值始终为CurrentYear - BornYear。这意味着在代码中的该点，age 根据这些变量的当前值设置为 CurrentYear - BornYear。这两个变量都未初始化，因此它们的值是不确定的。

您需要将age的计算移至之后您读取CurrentYear和BornYear:

int CurrentYear;
int BornYear;
int age;

printf("What year is it?\n");
scanf("%d", &CurrentYear);
printf("What year you were born?\n");
scanf("%d", &BornYear);

age = CurrentYear - BornYear;
printf("You are %d years old\n", age);