c - 我在 C 程序编码中遇到未知错误

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这是我的代码:

#include <stdio.h>

main()
{
int yearcounter = 0;
int monthcounter = 0;
int monthcounter2 = 0;
int extramonths = 0;
int monthsalive = 0;
int month;
int day;
int year;
int monthto;
int dayto;
int yearto;
printf("What date were you born? Enter mm/dd/fullyear with no dashes.\n");
scanf("  %d/%d/%d", &month, &day, &year);
printf("What is today's date?\n");
scanf("  %d/%d/%d", &monthto, &dayto, &yearto);

if

(year < 0 && year <= yearto);
year++;
yearcounter++;

if 

(month > 0 && month <= 12);
month++;
monthcounter++;

if 

(monthto > 0 && monthto <= 12);
{
monthto++;
monthcounter2++;
}
extramonths = monthcounter - monthcounter 2;

if

(extramonths <= 0);
{
yearcounter = yearcounter - 1;
}
monthsalive = yearcounter * 12;

printf("You've been alive %d years.\n", yearcounter);
printf("You've been alive about %d months.\n", monthsalive);
return 0;
}

错误是:

main.c:41:49: error: expected ';' before numeric constant ; extramonths = monthcounter - monthcounter 2;

有人可以帮我吗？

Answer 1

你认为这会做什么？

if

(year < 0 && year <= yearto);
year++;
yearcounter++;

(提示:if 语句末尾有一个分号，并且运算周围没有括号。)

你真正想要的是:

if (year < 0 && year <= yearto)
{
    year++;
    yearcounter++;
}

<小时/>

在这一行:

extramonths = monthcounter - monthcounter 2;

您的意思是将多月计数器加 2 吗？为此，您需要一个乘法运算符!

extramonths = monthcounter - monthcounter * 2;

或者也许您打算使用变量monthcounter2，在这种情况下，空间就不好。

extramonths = monthcounter - monthcounter2;