c - 尝试在 c 中分配内存函数？

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我一直在尝试调用这个函数，但我不断收到错误“找不到标识符”(是的，我知道我的变量名不是最实用的)。

#include <stdio.h>
#include <stdlib.h>

typedef struct _POOL
{
    int size;
    void* memory;

} Pool;

int main()
{
    printf("Enter the number of bytes you want to allocate\n");
    int x = getchar();
    allocatePool(x);

    return 0;
}

Pool* allocatePool(int x)
{
    Pool* p = (Pool*)malloc(x);
    return p;
}

Answer 1

也许你想做的应该是这样的:

#include <stdio.h>
#include <stdlib.h>

typedef struct pool
{
    int size;
    void* memory;
} pool;

pool allocatePool(int x);

int main (int argc, char *argv[])
{
    int x = 0;
    pool *p = NULL;
    printf("enter the number of bytes you want to allocate//>\n");
    if (scanf("%d", &x) == 1 && x > 0 && (p = allocatePool(x)) != NULL)
    {
        // Do something using p
        // ...
        // Treatment is done, now freeing memory
        free(p->memory);

        free(p);
        p = NULL; // Not useful right before exiting, but most often good practice.
        return 0;
    }
    else
    {
        // Show a message error or do an alternative treatment
        return 1;
    }
}

pool allocatePool(int x)
{
    pool *p = malloc(sizeof(pool));
    if (p != NULL)
    {
        p->memory = malloc(x);
        p->size = (p->memory == NULL) ? 0 : x;
    }
    return p;
}