c - 程序不运行。说我正在尝试为指针赋值

Question

我正在尝试将文件读入数组，但代码未运行。说我正在尝试为指针赋值。

 #include <stdio.h>

int main(void)
{
    FILE *ifile;
    float num;
    float*numbers[8001];
    float pointer = numbers;
    int i = 0;

    ifile = fopen("lotsOfNumbers.txt", "r");
    if (ifile == NULL) {
        printf("File not found!! Exiting.\n");
    }
    else {
        while (fscanf(ifile, "%f ", &num) != EOF) {

            //printf("I read %d from the file. \n", num);
            numbers[i] = &num;

            if (i < 8801) {
                i++;
            }
            else return 0;
        }
    }

    fclose(ifile);
}

Answer 1

您的代码中有很多错误。您可能想要这个:

#include <stdio.h>

int main(void)
{
  FILE *ifile;
  float num;
  float numbers[8001];    // you just need an array of float, no pointers needed
  int i = 0;

  ifile = fopen("lotsOfNumbers.txt", "r");
  if (ifile == NULL) {
    printf("File not found!! Exiting.\n");
  }
  else {
    while (fscanf(ifile, "%f ", &num) != EOF) {  // &num instead of num

      printf("I read %f from the file.\n", num); // use %f for printing a float, not %d
      numbers[i] = num;

      if (i < 8001) {    // 8001 instead of 8801
        i++;             // using a constant or a #define avoids this kind of errors
      }
      else
        return 0;
    }

    fclose(ifile);   // close file only if it has been opened sucessfully
  }
    // fclose(ifile);  // that was the wrong place for fclose
}

解释在评论中。