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c - 需要算法来解决C中的移位问题

转载 作者:行者123 更新时间:2023-11-30 21:31:09 24 4
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a.txt    
#0 p0=1 p100=0 p4=0 p7=1
#10 p5=1 p100=1 p8=0

如果我有一个文件名a.txt我实际上要处理诸如类次特定px之类的内容例如如上所示p0,p1,p2 。例如,如果在我的命令行中将有开关来定义哪个 px需要按 #shift_value 移动比如

-shift p100=shift_value15:p5=shift_value4:p7=shift_value2

因此文件中的内容将更改如下:

a.txt(result)
#0 p0=1 p4=0
#2 p7=1
#10 p8=0
#14 p5=1
#15 p100=0
#25 p100=1

So from the switch to enable shifting for the specific px with #shift_value,when p100 if is at #0 then will be shifted by 15 to become at #15 where p100 at #10 will be then shifted to #25 and so the rest of the px are in the same manner.

我需要一种可以执行此行为的算法,该算法通过使用 a.txt 中的内容转换为 a.txt(结果)。

最佳答案

像这样(省略错误处理,如果strtok_r可以使用,则删除strtok_r):

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *strtok_r(char *str, const char *delims, char **store){
char *p, *wk;
if(str != NULL){
*store = str;
}
if(*store == NULL) return NULL;
*store += strspn(*store, delims);//skip delimiter
if(**store == '\0') return NULL;
p=strpbrk(wk=*store, delims);
if(p != NULL){
*p='\0';
*store = p + 1;
} else {
*store = NULL;
}
return wk;
}

#define SHIFT_KEYWORD "shift_value"

typedef struct pair {
char *key;
int val;
} Pair;

int cmp(Pair *a, Pair *b){
return strcmp(a->key, b->key);
}

Pair *parse_command(const char *commands, int *num_cmd){
char *pc, *cmd = strdup(commands);

if(NULL!=(pc = strtok(cmd, " ")) && strcmp(pc, "-shift")!=0){
fprintf(stderr, "command format error!\n");
*num_cmd = 0;
free(cmd);
return NULL;
}
char *p;
pc = strtok(NULL, " ");
*num_cmd=1;
for(p=pc;NULL!=(p=strchr(p, ':'));++p){
++*num_cmd;//count command
}
Pair *cmds = calloc(*num_cmd, sizeof(Pair));
int c = 0;
char *pr1, *pr2;
for(p = pc;NULL!=(p=strtok_r(p, ":", &pr1));p=NULL){
const int len = sizeof(SHIFT_KEYWORD)-1;
for(;NULL!=(p=strtok_r(p, "=", &pr2));p=NULL){
if(strncmp(p, SHIFT_KEYWORD, len)==0)
cmds[c++].val = atoi(p + len);
else
cmds[c].key = strdup(p);
}
}
qsort(cmds, *num_cmd, sizeof(Pair), (int (*)(const void*,const void*))cmp);
free(cmd);
return cmds;
}

int count_element(FILE *fp){
int ch, count =0;
while(EOF!=(ch=fgetc(fp))){
if(ch == '=')
++count;
}
rewind(fp);
return count;
}

typedef struct vec {
int value;
Pair pair;
} Vec;

int cmpv(const void *x, const void *y){
Vec *a = (Vec*)x;
Vec *b = (Vec*)y;
return a->value != b->value ? a->value - b->value : strcmp(a->pair.key, b->pair.key);
}

int main(void){
const char *command ="-shift p100=shift_value15:p5=shift_value4:p7=shift_value2";
int num_cmd;
Pair *cmd_list;

cmd_list=parse_command(command, &num_cmd);

FILE *fp=fopen("a.txt","r");
int num_vec = count_element(fp);
Vec v[num_vec];
char buff[1024];
int c=0;
while(fgets(buff, sizeof(buff), fp)){
char *p;
int value;
p=strtok(buff, " \n");
if(*p == '#')
value = atoi(p+1);
else {
fprintf(stderr, "data format error\n");
exit(1);
}
for(;NULL!=(p=strtok(NULL, " \n"));++c){
Pair *cmd;
char *pr, *key;
int event;
pr=strchr(p, '=');
*pr = '\0';
key = strdup(p);
event = atoi(pr+1);
v[c].value = value;
v[c].pair.key = key;
v[c].pair.val = event;
cmd = bsearch(&v[c].pair, cmd_list, num_cmd, sizeof(Pair), (int (*)(const void*,const void*))cmp);
if(cmd){
v[c].value = value + cmd->val;
}
}
}
fclose(fp);
qsort(v, num_vec, sizeof(Vec), cmpv);

//stdout -> fp = fopen("a.txt", "w");
int i, pre_value=-1;
for(i=0;i<num_vec;++i){
if(pre_value != v[i].value){
if(pre_value!=-1)
fprintf(stdout, "\n");
fprintf(stdout, "#%-2d", pre_value=v[i].value);
}
fprintf(stdout, " %s=%d", v[i].pair.key, v[i].pair.val);
free(v[i].pair.key);
}
for(i=0;i<num_cmd;++i){
free(cmd_list[i].key);
}
free(cmd_list);
return 0;
}

关于c - 需要算法来解决C中的移位问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17880175/

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