c - 实现线性搜索

Question

问题:将最多 6 对姓名和年龄读取到两个单独的数组中，并使用线性搜索来定位目标姓名并打印该人的年龄。这两个数组称为姓名和年龄:

我收到很多错误..我不确定是否将数组传递给函数..

  #include <stdio.h>
#define ASIZE 20
#define RECSIZE 6

struct record {
    char name[ASIZE];
    int age[ASIZE];
};
struct record na[RECSIZE];

int linearSearch(struct record *a, char *find)
{
int x;
for(x=0; x<RECSIZE; x++)
{
//  if(na[x].name==find[x])
if(a->name[x]==find[x])
    {
        return x;
    }
}
return -1;
 }

int main()
{
    int i;

    for (i=0; i<RECSIZE; i++)
{
printf("Enter name: ");
scanf("%s",na[i].name);
printf("Enter age: ");
scanf("%i",&na[i].age);
}   

printf("Enter the Search name: ");
char temp[ASIZE];
scanf("%s",temp[ASIZE]);


int result;
result=linearSearch(&na, &temp[]);
printf("%i", result);
    return 0;
    }

请帮忙。

错误在于: 结果=线性搜索(&na, &temp[]);

Answer 1

#include <stdio.h>
#include <string.h>

#define ASIZE 20
#define RECSIZE 6

struct record {
    char name[ASIZE];
    int age;
};

struct record na[RECSIZE];

int linearSearch(struct record *a, char *find){
    int x;
    for(x=0; x<RECSIZE; x++){
        if(strcmp(a[x].name, find)==0)
            return x;
    }
    return -1;
}

int main(){
    int i;

    for (i=0; i<RECSIZE; i++){
        printf("Enter name: ");
        scanf("%s", na[i].name);//No protection when entered past the buffer
        printf("Enter age: ");
        scanf("%i", &na[i].age);
    }

    printf("Enter the Search name: ");
    char temp[ASIZE];
    scanf("%s", temp);

    int result;
    result=linearSearch(na, temp);
    printf("%i", result);
    return 0;
}