c - Hangman - 如何正确计算玩家的错误猜测次数？

Question

关闭。此题需要 details or clarity 。目前不接受答案。

---

想要改进这个问题吗？通过 editing this post 添加详细信息并澄清问题.

已关闭 8 年前。

Improve this question

现在我的游戏正确计数了我正确的字符数，但是如果不匹配字符的大约等于字符串的长度，则不会计数。我一直在尝试修改这段代码一段时间，但它仍然无法修复。这是我的代码:

/*includes and defines*/
     #include <stdio.h>
     #include <string.h>
     #define SIZE 50

     /*prototype definitions*/
     int compareString(char *, char *);

     int main(void){

        char word[SIZE];
        char input[SIZE];
        char guess[SIZE];
        int count = 0;
        int wrong = 0;
        int incorrect = 0;
        int right = 0;
        int len = 0;

        printf("Please enter the word you would like to have to guess.\nThen hand your computer over to the person you would like to have play:");
        fgets(word, SIZE, stdin);

        len = strlen(word);

        printf("Please guess one letter for the %d letter word!\n", len - 1);

        do{

            fgets(input, SIZE, stdin);

            for(count = 0; count < len - 1; count++){
                if(input[0] == word[count]){
                    printf("that letter is in the %d spot\n", count + 1);
                    ++right;
                }
                /*I know the problem lies here but i'm not sure how to fix it I've tried not using len-1         and just using len, I've tried not resetting the amount wrong. Everything!*/
                else if (input[0] != word[count]) {
                    ++wrong;
                        if(wrong == len - 1){
                            ++incorrect;
                        }
                    wrong = 0;
                }
            }

        }while(incorrect < 6 && right < len - 1);


        return 0;
     }

我知道问题就出在这里，播放器的代码设置错误。但是我不知道如何解决它。我尝试过不使用 len-1 而只使用 len，我尝试过不重置错误的金额。

else if (input[0] != word[count]) {
                        ++wrong;
                            if(wrong == len - 1){
                                ++incorrect;
                            }
                        wrong = 0;
                    }

Answer 1

问题在于您尝试增加不正确的方式。只需使用 wrong 作为 bool 值，您将用它来决定是否需要增加in Correct

解决方案如下:

#include <stdio.h>
#include <string.h>
#define SIZE 50

/*prototype definitions*/
int compareString(char *, char *);

int main(void){

  char word[SIZE];
  char input[SIZE];
  char guess[SIZE];
  int count = 0;
  int wrong = 1;
  int incorrect = 0;
  int right = 0;
  int len = 0;

  printf("Please enter the word you would like to have to guess.\nThen hand your computer over to the person you would like to have play:");
  fgets(word, SIZE, stdin);

  len = strlen(word);

  printf("Please guess one letter for the %d letter word!\n", len - 1);

  do{

    fgets(input, SIZE, stdin);
    wrong = 1;
    for(count = 0; count < len - 1; count++){

      if(input[0] == word[count]){
        printf("that letter is in the %d spot\n", count + 1);
        wrong = 0;
        ++right;
      }
      /*I know the problem lies here but i'm not sure how to fix it I've tried not using len-1         and just using len, I've tried not resetting the amount wrong. Everything!*/
    }
    if(wrong) {
      incorrect++;
    }

  }while(incorrect < 6 && right < len - 1);


  return 0;
}