c - C 中的 2 元素数组列表

Question

我正在尝试获取一个索引的整数列表，即我放入 aab，我得到 97 97 98，我希望每个索引都像在常规数组中一样。

typedef struct element {   
    struct element *next;
    int value;
    int index;
} listElements;

事情是当我分配指针 ->索引=整数; integer++ 然后 printf 它，值列按照应有的 a a b 打印，但索引列打印 2 0 1 。我哪里出错了？

编辑:更多代码

int addToList ( listElements *list, int character, int integer ) {
    listElements *pointer, *element;
    pointer = list;

    while ( pointer -> next != NULL ) {
        pointer = pointer -> next;
    }

    element = ( listElements* ) malloc ( sizeof ( listElements ) );
    element -> value = character;
    element -> index = integer;
    integer++;
    element -> next = NULL;
    pointer -> next = NULL;

    return integer;
}

void printList ( listElements *list ) {
    listElements *pointer = list;

    while ( pointer != 0 ) {
        printf ( "%d %d\n", pointer -> value, pointer -> index );
        pointer = pointer -> next;
    }
}


int main () {

    char character;

    first = ( listElements* ) malloc ( sizeof ( listElements ) );
    first -> value = character = getchar ();
    first -> index = 0;
    first -> next = NULL;


    while ( ( character = getchar () ) != 'Q' ) {
        first -> index = addToList ( first, character, first -> index );
    }

    printList ( first );

    return 0;
}

Answer 1

索引不正确(2 0 1 而不是 0 1 2。如果这就是您所要求的)，因为您正在这样做:

first -> index = addToList ( first, character, first -> index );

您正在将返回值分配给第一个元素的索引。

将其更改为如下所示:

int index = 1; // declare at right position in main.
while ( ( character = getchar () ) != 'Q' )
{
    index = addToList ( first, character, index );
}