c - 如何检测 X 的对角线数

Question

我正在尝试编写一个程序，如果连续有 n 个 X 或 O，则该程序将调用函数 win。我对向上倾斜的对角线胜利感到困难。有人可以就我应该改变什么提供任何建议吗？提前致谢。它调用无限循环而不是返回 true。

bool left_diag_win(char **board, int num_rows, int num_cols) {
    int i;

    if (board[0][0] == '*') {
        return false;
    }

    for (i = 1; i < num_rows; ++i) {
        if (board[i][i] != board[0][0]) {
            return false;
        }
    }
    return true;
}

bool right_diag_win(char **board, int num_rows, int num_cols) {
    int i;

    if (board[0][num_cols - 1] == '*') {
        return false;
    }

    for (i = 1; i < num_rows; ++i) {
        if (board[i][num_cols - i - 1] != board[0][num_cols - 1]) {
            return false;
        }
    }
    return true;
}

Answer 1

您的代码似乎是正确的，但您可能在其他地方遇到问题。这是一个其行为符合预期的示例:

#include <stdbool.h>
#include <stdio.h>

bool left_diag_win(char **board, int num_rows, int num_cols) {
    if (board[0][0] == '*') {
        return false;
    }
    for (int i = 1; i < num_rows; ++i) {
        if (board[i][i] != board[0][0]) {
            return false;
        }
    }
    return true;
}

bool right_diag_win(char **board, int num_rows, int num_cols) {
    if (board[0][num_cols - 1] == '*') {
        return false;
    }
    for (int i = 1; i < num_rows; ++i) {
        if (board[i][num_cols - i - 1] != board[0][num_cols - 1]) {
            return false;
        }
    }
    return true;
}

int main(void) {
    char *matrix1[] = { "X****", "*X***", "**X**", "***X*", "****X" };
    char *matrix2[] = { "****X", "***X*", "**X**", "*X***", "X****" };

    printf("matrix:\n");
    for (int i = 0; i < 5; i++) {
        printf("%s\n", matrix1[i]);
    }
    printf("left-diagonal: %d\n", left_diag_win(matrix1, 5, 5));
    printf("right-diagonal: %d\n\n", right_diag_win(matrix1, 5, 5));

    printf("matrix:\n");
    for (int i = 0; i < 5; i++) {
        printf("%s\n", matrix2[i]);
    }
    printf("left-diagonal: %d\n", left_diag_win(matrix2, 5, 5));
    printf("right-diagonal: %d\n\n", right_diag_win(matrix2, 5, 5));

    return 0;
}

输出:

matrix:
X****
*X***
**X**
***X*
****X
left-diagonal: 1
right-diagonal: 0

matrix:
****X
***X*
**X**
*X***
X****
left-diagonal: 0
right-diagonal: 1