c - 在c中对字符串数组进行排序，但程序崩溃

Question

已关闭。此问题需要 debugging details 。目前不接受答案。

---

编辑问题以包含 desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem 。这将有助于其他人回答问题。

已关闭 5 年前。

Improve this question

我正在循环访问一个文件以查找用户输入的匹配记录，然后我需要按升序打印它们。我的程序总是崩溃。我需要帮助。我编写了一些函数来完成这项工作。

static int myCompare (const void * a, const void * b)
{
    return strcmp (*(const char **) a, *(const char **) b);
}

void sort(const char *arr[], int n)
{
    qsort (arr, n, sizeof (const char *), myCompare);
}

void search_contact() {
    FILE * fp;
    bool found = false;
    char *records;
    fp = fopen("contact.txt", "r");
    system("cls");
    printf("\t*****SEARCH CONTACT*****");
    printf("\n\t Enter Mobile: ");
    char mobile[20];
    scanf("%s", mobile);
    char mobile1[20], name[20];    
    while (fscanf(fp, "%s %s", name, mobile1) != EOF) {
        if (strcmp(mobile, mobile1) == 0) {
            records = malloc(sizeof(name));
            strcpy(records,name);

            int i;
        //  printf(" %s", records);
            found = true;
        } else {
            found = false;
        }
    }
    if(found){
        int n = sizeof(records)/sizeof(records[0]);
         sort(records, n);
         int i;
         for (i = 0; i < n; i++)
            printf("%s \n", records[i]);
    }
    else{
        printf("\n No Records Found!");
    }
    fclose(fp);
    printf("\n\tPRESS ANY KEY TO CONTINUE");
    getch();
    main();
}

Answer 1

您希望 records 是一个字符串数组，所以它应该是:

char **records = NULL;
int num_records = 0;

然后，当您将字符串添加到记录数组时:

records = realloc(records, sizeof(*records) * (num_records + 1));
if (NULL == records) { // Handle failure }
records[num_records] = malloc(strlen(name) + 1);
if (NULL == records[num_records]) { // Handle failure }
strcpy(records[num_records], name);
num_records += 1;

并且不要忘记free()所有这些数据。