c - 为什么下面的代码不能正确输出所有测试用例？

Question

/*
*
*Program for finding total number of holes in a string.
*For example total number of holes in "ANUBHAV" is 4 and in "GOURAV" is 3
*
*/
#include <stdio.h>
#include<string.h>
// start of main function
int main(void) {
    int t,i = 0,hole = 0; // variable declaration
`   char str[100];
    scanf("%d",&t); // input number of test cases
    while(t--)
    {
        scanf("%s",str);  // input string
        while(i < strlen(str))
        {
            if(str[i] == 'B')
            {
                hole += 2;
            }
            else if(str[i] == 'A' || str[i] == 'D' || str[i] == 'O' || str[i] == 'P' || str[i] == 'Q' || str[i] == 'R' )
            {
                hole += 1;
            }

            i = i + 1;  
        }
        printf("%d",hole); //printing the total number of holes
    }
    return 0;
}

此代码在第一个测试用例(t)中输出正确，但在下一个测试用例中产生错误的输出。代码中有什么问题？请帮忙!提前致谢!

Answer 1

每次输入新字符串时，都需要初始化hole。你的代码还可以改进很多，检查一下

/*
*
*Program for finding total number of holes in a string.
*For example total number of holes in "ANUBHAV" is 4 and in "GOURAV" is 3
*
*/
#include <stdio.h>
#include <string.h>
// start of main function
int main(void)
{
    int hole; // variable declaration
    int count;
    char str[100];
    if (scanf("%d", &count) != 1)
        return -1; // Input Error
    for (int i = 0 ; i < count ; ++i)
    {
        hole = 0;
        if (scanf("%99s", str) != 1)
            return -1; // Input Error
        for (int j = 0 ; str[j] != '\0' ; ++j)
        {
            switch (str[j])
            {
                case 'B':
                    hole += 2;
                    break;
                case 'A':
                case 'D':
                case 'O':
                case 'P':
                case 'Q':
                case 'R':
                    hole += 1;
                    break;
            }
        }
        printf("Holes in %s -> %d\n", str, hole); //printing the total number of holes
    }
    return 0;
}