c - 由于一个分号，函数无法编译，我不知道为什么

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我正在尝试用 C 语言编写一个程序，但卡在一个无法编译的函数上。该函数旨在随机生成两个整数作为结构数组的单独部分，据我所知，它工作正常，只是无法编译。我收到的错误是第一个 '}'错误:预期的标识符或“(”这是实际的功能代码。如果有任何帮助，我将不胜感激。

struct nost * rnote(int measueres, int measuretime);
{


    int lengths[16*measures];

    int n = 0;
    for(int z = 0; z < measures; z++)
    {
        srand(time(NULL));

        float one = 0;

        float num = 0;

        do
        {
            num = rand()%100 //makes sure the number is 1-100

           if(num < 5){ num = 1/1}   //5% chance of whole note
            else { if (num < 15) {num = 1/2;}   //10% chance of half note  
                else { if(num < 45) {num = 1/4;}    //30%chance of quarter note
                        else{ if(num < 65) { num = 1/8;}    //20% chance of eigth note
                                else{ if( num < 80) {num = 1/16;}   //15%chance of sixteenth note
                                        else{ if(num < 90) { num = 3/4 ;}   //10% chance of dotted half
                                                else{ num = 3/8;}}}}}}  //10% chance of dotted quarter
                                                    //however, because  a measure can only have so many beats,
                                                    //smaler note engths will end up more likely to happen at 
                                                    //at the end of the measure

            if((one + num) <= measuretime) // makes sure that there are not too many beats in one measure
            {
                one = one+num;
                lengths[n] = num;
                n++; //moves n up one so that next lenght is in next spot of array
            }

        }while(one != measuretime);

    }

    int arraylength = n; // takes size of lentgh ^^^^ array and puts it in 
                                                        // the note array

    int notes[arraylength]; //the  actual notes

    for(int y = 0; y < arraylength; y++)
    {
        srand(time(NULL));
        int x = rand()%100;

        if(x < 17){ x = 1;} // makes it more likely by 17:8 odds for 1,3,5,8 in scale to appear
        else { if (x < 34) {x = 3;}     /// than for 2,4,6,7 to appear
                else { if(x < 51) {x = 5;}
                        else{ if(x < 68) { x = 8;}
                                else{ if( x < 76) {x = 2;}
                                        else{ if(x < 84) { x = 4;}
                                            else{ if(x < 92) { x = 6;}
                                                    else{ x = 7;}}}}}}}


        notes[y] = x;

    }

   static struct nost all[1024];

    for(int u = 0; u < arraylength; u++)
    {
        all[u].note = notes[u];
        all[u].length = lengths[u];
    }

    all[0].arraylength = arraylength;

    return all;
}

Answer 1

看起来您的函数是这样开始的:

struct nost * rnote(int measueres, int measuretime); { [....]
                   Extra Semi-Colon Before Body ~~~^