javascript - 从数组中返回奇数或偶数

Question

只是需要帮助来确定我在这个代码战挑战中做错了什么。

我知道这对某些人来说可能很容易，但请注意我只是 Javascript 的初学者。

挑战:

You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a method that takes the array as an argument and returns N.

例如:

[2, 4, 0, 100, 4, 11, 2602, 36] 应该返回 11。

[160, 3, 1719, 19, 11, 13, -21] 应该返回 160。

我的代码:

function findOutlier(integers){

    var even = [];
    var odd = [];

  for (var i = 0; i < integers; i++) {
    if (integers[i] % 2 === 0) {
        even.push(integers[i]);
    } else {
        odd.push(integers[i]);
    }

    if (even.length === 1) {
        return even;
    } else {
        return odd;
    }
  }
}

Answer 1

另一种可能的方式:

function myFunction(integers) {
  var odds = integers.filter(function(num) {return num % 2});
  var evens = integers.filter(function(num) {return !(num % 2)});
  return evens.length == 1 ? evens[0] : odds[0];
}

---

你可以看看这个 CodePen Demo 在 Mocha 中测试功能。