c - 为什么我无法扫描%c字符？

Question

c编程时，扫描字符串成功后，不是扫描字符。

char s[10],c;
scanf("%s",s);
scanf("%c",&c);
printf("%s\n",s);
printf("%c",c);

Answer 1

scanf手册:

specifier c:

Matches a sequence of characters whose length is specified by the maximum field width (default 1); the next pointer must be a pointer to char, and there must be enough room for all the characters (no terminating null byte is added). The usual skip of leading white space is suppressed. To skip white space first, use an explicit space in the format.

因此，将格式更改为“%c”。