c - ‘unary *’ 的类型参数无效(有 ‘int’ )

Question

很抱歉重复这个问题，但我无法理解(我认为我的问题是)指针。有人可以帮我解释一下吗？我已经浏览了大量的 stackoverflow 问题、c 教程，而且它最令人困惑，因为每个解决方案似乎都与另一个解决方案相矛盾 - 如果我看到我的代码被修复，我确信这将帮助我完全理解

1 #include <stdio.h>
2 getinput()
3 {
4 int *employeeSalary[5];
5 int i;
6         for(i=0;i<5;i++)
7         {
8                 printf("Enter details of employee no. %d :",i+1);
9                 scanf("%d",&employeeSalary[i]);
10         }
11 return(*employeeSalary);
12 }
13 
14 int payrise(int *employeeSalary[])
15 {
16 int *newSalary = ((employeeSalary*0.20)*100);
17 return(*newSalary);
18 }
19 
20 int highestSalary(int *newSalary)
21 {
22 int i = 0;
23 int biggestSalary;
24 int element;
25         if(newSalary[i] >= newSalary[i])
26         {
27                 biggestSalary = newSalary[i];
28                 element = i;
29         }
30 return(biggestSalary, element);
31 }
32 
33 void display(int *employeeSalary, int *newSalary, int biggestSalary, int element)
34 {
35 printf("The old salary was %d and the new one is %d ", employeeSalary, newSalary);
36 printf("The biggest salaray is %d in element %d", biggestSalary, element);
37 }
38 
39 
40 int main()
41 {
42 int initialSalary = getinput();
43 int payIncrease = payrise(initialSalary);
44 int largestSalary = highestSalary(payIncrease);
45 display(initialSalary, payIncrease, largestSalary);
46 return(0);
47 }

这些是我遇到的错误

11: error: invalid type argument of ‘unary *’ (have ‘int’)
16: error: invalid operands to binary * (have ‘int ***’ and ‘double’) 
17: error: invalid type argument of ‘unary *’ (have ‘int’)
45: error: too few arguments to function ‘display’

Answer 1

在第 2 行，您有一个看起来像没有返回类型的函数声明，请尝试添加一个。