c - 结构数组错误

Question

我似乎无法理解如何从用户输入复制到数组结构中，我研究了整个网站，发现了很多变体，但没有一个对我有帮助的示例:

#include <stdio.h>
#include <string.h>

struct member 
{
    char name;
    int age;
    char state;
};

int main() 
{
     int i,r,iyr;
     char name, stabr;
     struct member record[49];

    for(r=0;r<49;r++)
    {
        printf ( "\nEnter the name of the family member \n");
        printf ("\nCount is %d \n",r+1);
        scanf ( "%s", &name);
        strcpy(record[r].name, name);
        printf ( "\nEnter the age of the family member \n");
        scanf ( "%d", &iyr);
        record[r].age=iyr;
        printf ( "\nEnter the abbreviated state name of the family member \n");
        scanf ( "%s", &stabr);
        strcpy(record[r].state, stabr);

    }
    for(i=0; i<49; i++)
     {
         printf("     Records of Family : %d \n", i+1);
         printf(" Name is: %s \n", record[i].name);
         printf(" Age is: %d \n", record[i].age);
         printf(" State is: %s\n\n",record[i].state);
     }
     return 0;
}

预先感谢您的帮助。

Answer 1

您使用单个字符来存储名称和状态。你没有分配内存。当您分配内存时，请使用指针表示法而不是数组，因为数组将具有无法修改的常量指针。请记住释放内存。

#include <string.h>
#include <stdlib.h>
typedef struct member
{
    char name[50]; // You were using single character for storing a name of multiple character and state
    int age;
    char state[50];
}members;
int main(void)
{
    //When you are allocating memory use pointer notation than array
    //because array will have const pointer which cannot be modified
    members *record = (members *)malloc(49*sizeof(members)); // you are not allocating memory
    int r;
    for(r=0;r<2;r++)
    {
        printf ( "\nEnter the name of the family member \n");
        printf ("\nCount is %d \n",r+1);
        scanf ( "%s", &record[r].name);
        printf ( "\nEnter the age of the family member \n");
        scanf ( "%d", &record[r].age);
        printf ( "\nEnter the abbreviated state name of the family member \n");
        scanf ( "%s", &record[r].state);

    }
    for(r=0; r<2; r++)
    {
        printf("     Records of Family : %d \n", r+1);
        printf(" Name is: %s \n", record[r].name);
        printf(" Age is: %d \n", record[r].age);
        printf(" State is: %s\n\n",record[r].state);
    }

    free(record); // Remember to free the memory

    return 0;
}