javascript - 使用 AJAX 登录，其中数据位于文本文件中

Question

我正在使用 ajax 登录，其中数据存储在文本文件中，由于某种原因我的登录不起作用，它显示登录失败以及 php 回显登录:错误。这是我的 javascript 代码位:

//Logs in the user
  btnLoginForm.addEventListener( "click", loginUser);

    function loginUser() {
        var ajax = new XMLHttpRequest();
        ajax.onreadystatechange = function() {
        if (this.readyState == 4 && this.status == 200) {
            ajUserDataFromServer = JSON.parse( this.responseText );

            console.log("The return from the server = " +   ajUserDataFromServer);

            if( ajUserDataFromServer.login == "ok" ){

                console.log("WELCOME");
              } 

            else 
                {

                console.log("LOGIN FAIL - TRY AGAIN");  

                }
            }
        }
      ajax.open( "POST", "api_login_users_wm.php" , true );
      var jFrmLogin = new FormData( frmLogin );
      ajax.send( jFrmLogin );
    }   

这是 php:

session_start();

// Load all the users and decode them to an array
$sajUsers = file_get_contents('webshop_mandatory_users.txt');
$ajUsers = json_decode($sajUsers);//turns the string into an array.

// Data comes from the browser
$sEmail = $_POST['txtEmail'];
$sPassword  = $_POST['txtPassword'];


// begin looping through the array.
for( $i = 0; $i < count($ajUsers) ; $i++ ) {

    //check if the data from the frontend matches any date in the backend - Check each one, one by one.
    if ($sEmail == $ajUsers[$i]->email && $sPassword == $ajUsers[$i]->password) {     //checks if the value of the username is equal to the value in the array.
        echo $sjResponse = '{"login":"ok"}';
        exit; //end the if statement and exit if it works.
    } else {
        echo $sjResponse = '{"login":"error"}'; // it didnt work.
        exit;
    }
}


?>

Answer 1

此处您的结果将仅与第一个元素匹配。所以你需要使用标志变量来匹配数据

$match_found = false;
for( $i = 0; $i < count($ajUsers) ; $i++ ) {

    //check if the data from the frontend matches any date in the backend - Check each one, one by one.
    if ($sEmail == $ajUsers[$i]->email && $sPassword == $ajUsers[$i]->password) {     //checks if the value of the username is equal to the value in the array.
        $match_found = true;
        break;
    } 
}

if($match_found )
{
    echo '{"login":"ok"}';
}
else
{
    echo '{"login":"ok"}';
}
exit;