c - C 中标准输入的内存泄漏

Question

我的代码遇到了内存泄漏问题。我相信它来自 stdin 。我尝试关闭(0)，但没有成功。下面是我的代码

 char line[MAX_BUFFER] = {};
    char *commands;
    while(!feof(stdin)) {
         fputs("? ",stdout);

        if(fgets(line, MAX_BUFFER , stdin))
        {
            Command cmd = {};
            commands =  parse(&cmd, line);
            printf("%s",commands);
           free(commands);

         }

    }

    return 0;

我的parse.c基本上就是这样做的

    char result[250] = "some text string here";
    char *target  = malloc(sizeof(char) * 250);
    target = strdup(result);
    return target

我的 valgrind 输出看起来像这样

==26303== FILE DESCRIPTORS: 3 open at exit.
==26303== Open file descriptor 2: /dev/pts/4
==26303==    <inherited from parent>
==26303== 
==26303== Open file descriptor 1: /dev/pts/4
==26303==    <inherited from parent>
==26303== 
==26303== Open file descriptor 0: /dev/pts/4
==26303==    <inherited from parent>
==26303== 
==26303== 
==26303== HEAP SUMMARY:  
==26303==     in use at exit: 500 bytes in 2 blocks
==26303==   total heap usage: 4 allocs, 2 frees, 545 bytes allocated
==26303== 
==26303== 500 bytes in 2 blocks are definitely lost in loss record 1 of 1

Answer 1

strdup() 和 malloc() 都在分配内存!您可以删除 parse.c 中的第二行并编辑第三行以表示

char * target = strdup(result);

它会工作得很好。

另外，在使用完内存后，不要忘记使用 free(pointerToMemoryAllocation) 释放内存