c - 将大整数txt文件读入二维数组

Question

尝试创建一个程序，在大型文本文件中进行推理并将其填充到行+列中。最终我将不得不计算最佳路径，但在实现可以存储值的数组时遇到麻烦。

#include <stdio.h>
#include <stdlib.h>

//max number of characters to read in a line. //MAXN=5 means 4 chars are read, then a \0 added in fgets.  See reference for functionality

#define  MAXN  100L 
int main(void)   //char** argv also ok {
    int i=0, totalNums, totalNum,j=0;
    size_t count;
    int numbers[100][100];
    char *line = malloc(100);
    FILE* inFile ;
    inFile = fopen("Downloads/readTopoData/topo983by450.txt", "r");   //open a file from user for reading

    if( inFile == NULL) {  // should print out a reasonable message of failure here         
        printf("no bueno \n");
        exit(1);
    }

    while(getline(&line,&count, inFile)!=-1) {
        for(;count>0; count--,j++)
            sscanf(line, "%d", &numbers[i][j]);
            i++;
    }

    totalNums = i;
    totalNum = j;
    for(i=0;i<totalNums; i++){
      for(j=0;j<totalNum;j++){
        printf("\n%d", numbers[i][j]);
       }
    }   
    fclose(inFile);
    return 0; 
}

Answer 1

count 并不能告诉你有多少个数字。进一步: sscanf(line, "%d", &numbers[i][j]);每次都会扫描相同的号码。

所以这个

    for(;count>0; count--,j++)
        sscanf(line, "%d", &numbers[i][j]);

应该是这样的:

    j = 0;
    int x = 0;
    int t;
    while(sscanf(line + x, "%d%n", &numbers[i][j], &t) == 1)
    {
        x += t;
        ++j;
    }

其中 x 与 %n 一起帮助您在扫描数字后移动到字符串中的新位置。

这是一个扫描字符串中数字的简化版本:

#include <stdio.h>

int main(void) {
    char line[] = "10 20 30 40";
    int numbers[4];
    int j = 0;
    int x = 0;
    int t;
    while(j < 4 && sscanf(line + x, "%d%n", &numbers[j], &t) == 1)
    {
        x += t;
        ++j;
    }
    for(t=0; t<j; ++t) printf("%d\n", numbers[t]);
    return 0;
}

输出:

10
20
30
40