C 没有正确看到我的函数？

Question

我是 C 新手。我有一个定义如下的函数:

/*
 * Draws an image in mode3 USING DMA.
 * int x x coordinate 
 * int y y coordinate
 * int width Width of the image (Note may not be the same width as the GBA)
 * int height Height of the image (Note may not be the same height as the GBA)
 * const u16* pointer to the first element in the image
 */
void drawImage3(int x, int y, int width, int height, const u16* image)
{
    int r;
    for (r=0; r<height; r++) {  

            DMA[3].src = &image;
            DMA[3].dst = &videoBuffer[OFFSET(x+width, y, 240)];
            DMA[3].cnt = width | DMA_SOURCE_FIXED| DMA_ON | DMA_DESTINATION_INCREMENT; 
            image = &image + (r * width);

    }

}

在我的主程序中包含的 .h 文件中，我有以下内容:

void drawImage3(int x, int y, int width, int height, const u16* image);

其中 u16 表示无符号短整型，并在其他地方定义。

这些也都在我的 .h 文件中:

extern unsigned short *videoBuffer;
extern const unsigned short *pt; 

在另一个 h 文件中是一个由 1024 个常量无符号 Short 组成的数组。

在我的 main.c 文件中，我这样调用我的函数:

pt = imgArray;
drawImage3(25,25, img_WIDTH, img_HEIGHT, pt);

我收到很多错误。

Program.c:22: error: data definition has no type or storage class
Program.c:22: error: type defaults to 'int' in declaration of 'pt'
Program.c:22: error: conflicting types for 'pt'
myLib.h:21: note: previous declaration of 'pt' was here
Program.c:22: error: initializer element is not constant
Program.c:23: error: expected declaration specifiers or '...' before numeric constant
Program.c:23: error: expected declaration specifiers or '...' before numeric constant
Program.c:23: error: expected declaration specifiers or '...' before numeric constant
Program.c:23: error: expected declaration specifiers or '...' before numeric constant
Program.c:23: error: expected declaration specifiers or '...' before 'pt'
Program.c:23: error: data definition has no type or storage class
Program.c:23: error: type defaults to 'int' in declaration of 'drawImage3'
Program.c:23: error: conflicting types for 'drawImage3'
myLib.h:117: note: previous declaration of 'drawImage3' was here

对这里发生的事情有什么想法吗？

--------编辑

是的，奥利，你对第一个错误的看法是正确的。谢谢!我已经编辑了我的函数，并且该错误消失了。我还制作了我的 *pt 和 extern。

程序.c:

//Philip Johnson
#include <stdio.h>
#include "img.h"
#include <unistd.h>
#include "myLib.h"
#include "text.h"

typedef struct        // This typedef defines a new type called MOVOBJ
{                     // which are structures that hold all the info for
    int row;          // a single movable object
    int col;
    int rdel;
    int cdel;
    u16 color;

} MOVOBJ;

MOVOBJ newcharacter, car1, car2, car3;
int size = 5;
int speed = 2;
int checkforend = 0;
pt = imgArray;
drawImage3(25,25, img_WIDTH, img_HEIGHT, pt);
int main(){ //....and so on from there

Answer 1

您的意思可能是 u16* pt = imgArray; - 如果您在 C 中声明新变量，则必须给出类型。