c - C语言中的链表

Question

我正在尝试一个示例链接列表程序。下面的代码有什么问题？当我尝试访问这些值时......出现段错误。我无法访问根目录之外的值。以下内容有什么问题？

#include<stdio.h>
#include<stdlib.h>

struct node{
    int val;
    struct node* next;
};

void create(int n,struct node** ref){
    struct node *temp,*newnode;
    newnode=(struct node*)calloc(1,sizeof(struct node));
    newnode->val=n;
    newnode->next=NULL;
    if(*ref==NULL){
        *ref=newnode;
        temp=newnode;
    }
    else{
        temp->next=newnode; 
        temp=newnode;
    }
    return;
}  

int main(){
    struct node *root=NULL,*p;
    int n,i,j=1;
    while(j==1){
        printf("enter the value...\n");
        scanf("%d",&n);
        create(n,&root);
        //printf("%d",root->val);
        printf("Press 1 to continue..\n");
        scanf("%d",&j);
    }
    p=root;
    while(p!=NULL){
        printf("%d-",p->val);
        p=p->next;
    }
    printf("\n");
    return 0;
}

Answer 1

我认为您只需将 temp 声明为静态即可。至少这对我有用:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>

struct node{
  int val;
  struct node* next;
};

void create(int n,struct node** ref){
  static struct node *temp;
  struct node *newnode;

  newnode=(struct node*)calloc(1,sizeof(struct node));
  newnode->val=n;
  newnode->next=NULL;
  if(*ref==NULL){
    *ref=newnode;
    temp=newnode;
  }
  else{
    temp->next=newnode; 
    temp=newnode;
  }

  return;
}

输出:

enter the value...
1
Press 1 to continue..
1
enter the value...
2
Press 1 to continue..
1
enter the value...
3
Press 1 to continue..
0
1-2-3-