c++ - 调试断言失败缓冲区!= NULL

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你好，我有一个大学项目，用任何可能的语言读取 Wav 文件，所以我选择了 C/C++ 我认为我一切都正确，但我一直在做一件事c 项目我总是收到此消息“Buffer!= NULL”

完整代码:

int main (){
    //char id[10];
    FILE *wav;
    wav=fopen("sound.wav","rb");

    if(wav){
        BYTE wav_id[5], *sound_buffer;      
        DWORD size;

        short format_tag, channels, block_align, bits_per_sample;
        DWORD format_length, sample_rate, avg_bytes_sec,datasize,i;

        fread(&wav_id,sizeof(BYTE),4,wav);
        wav_id[sizeof(BYTE)+3]=0;   

        if (!memcmp(&wav_id,"RIFF",4)) {
            fread(&size,sizeof(DWORD),1,wav);
            fread(&wav_id,sizeof(BYTE),4,wav); 
            if (!memcmp(&wav_id,"WAVE",4)) { //this is probably a wave file since it contained "WAVE" 

                fread(&wav_id,sizeof(BYTE),4,wav); //read in 4 bytes "fmt "; 
                fread(&format_length,sizeof(DWORD),1,wav);
                fread(&format_tag, sizeof(short), 1, wav); 
                fread(&channels, sizeof(short),1,wav); 
                fread(&sample_rate, sizeof(DWORD), 1, wav); 
                fread(&avg_bytes_sec, sizeof(short), 1, wav); 
                fread(&block_align, sizeof(short), 1, wav); 
                fread(&bits_per_sample, sizeof(short), 1, wav); 
                fread(&wav_id, sizeof(BYTE), 4, wav); //read in 'data' 
                fread(&datasize, sizeof(DWORD), 1, wav); //how many bytes of sound data we 
                sound_buffer=(BYTE *)malloc(sizeof(BYTE) * datasize);
                fread(sound_buffer, sizeof(BYTE), datasize, wav);  // i trace the problem to this line the whole above code seems to run smooth 
            }
            cout << "\n The file is Riff but it's not a wav file"<<endl;
        }
        else {
            cout <<"\nNOT a Wav File\n"<<endl;}

        }
    else {
        cout <<"\nFile wasn't opened\n"<<endl;
    }

    system("pause");
}

Answer 1

正如您的错误所示-

Error 2 error C2664: 'strcmp' : cannot convert parameter 1 from 'BYTE [5]' to 'const char *'

您无法将 BYTE [5] 数据类型传递给字符串比较函数。它对原型(prototype)无效。语法是-

int strcmp(const char *s1, const char *s2);

你的两个参数都必须是字符串!

但是您正在将 wav_id 传递给 strcmp。我认为这不是一个字符串-

strcmp(wav_id,"RIFF") // problem 
strcmp(wav_id,"WAVE") // problem

<小时/>

否则您可以使用 memcmp 来比较内存位置。原型(prototype)是-

int memcmp(const void *s1, const void *s2, size_t n);

两个参数都是void *，因此您可以向此函数传递任何类型的指针!

尝试以下更改-

if (!memcmp(&wav_id,"RIFF",4)) {
    fread(&size,sizeof(DWORD),1,wav);
    fread(&wav_id,sizeof(BYTE),4,wav); 
    if (!memcmp(&wav_id,"WAVE",4)) 
... }